Let n be Fritzs' car speed, and n+12 be the speed of the train. Then:
1/2 (n)=1/3 (n+12)
2n+24=3n
n=24 mph
n+12=36 mph
Fritz travels 12 miles to work.
30 min @24mph=12 miles
20 min @36mph=12 miles
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Answer:
49 litres of petrol are needed to travel from town X to town Y and back.
Step-by-step explanation:
Well, first off, the variable X and Y, as well as the distance given (124 km) aren't important pieces of information in this equation. They're only there to throw you off and confuse you.
25L of <em>p</em> (petrol) to make the entire journey. After the engine has been tuned, it requires 2% less <em>p</em> than before it was tuned.
2%/100 = 0.02
0.02 * 25L = 0.5L
25L - 0.5L = 24.5L
Now, don't forget, at the end of the word problem we're asked how many litres of <em>p</em> would be required to travel from <em>x</em> to <em>y</em> <em><u>AND BACK</u></em>. So it's not only 24.5L, it's double that (24.5 * 2 = 49L)
Good luck!!
Answer:y=2x+10
Cost is 22.00
Step-by-step explanation:
B=10 m=2
C=2(6)+10
C=12+10
C=22.00
Answer:
15 dollers
Step-by-step explanation:
Answer:
I hate to break it, but you ain't giving any information or numbers
