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Aleks [24]
3 years ago
14

Suppose f(x)=x^2. what is the graph of g(x)=f(3x)?​

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

D

Step-by-step explanation:

because since there is no negative sign in front of the 3x we automatially know there is no reflection so that rules out answers A and B. Then, since 3 is greater than 1 we can determine that it is a stretch which would rule out answer C so the answer is D

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4 0
2 years ago
What name best describes this polygon? trapezoid rectangle quadrilateral rhombus
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3 years ago
The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.
gtnhenbr [62]

Answer:

a) r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=4 \sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501  

r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5  

And the slope would be:  

m=\frac{64.5}{2000}=0.03225  

Now we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50  

\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425  

And we can find the intercept using this:  

b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27  

So the line would be given by:  

y=0.3225 x -0.27  

4 0
3 years ago
The temperature is -5°C at sunrise. By noon, the temperature changes by 6°C what could be the temperature at noon? answer asap !
Citrus2011 [14]

Answer:

the temperature is -5C which is negative so its behind the zero on a number line  and 6C is positive which is infront of the zero so it would be 1C by noon

Step-by-step explanation:

3 0
3 years ago
What is the solution to the following system of equations?<br><br> 3x - 2y = 4<br><br> x + 2y = 4
ivanzaharov [21]

Answer:

i have no clue lol

Step-by-step explanation:

i have no clue lol

4 0
3 years ago
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