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I am Lyosha [343]
3 years ago
14

What will be the range of the random numbers generated by the following code snippet? rand() % 50 + 5;

Computers and Technology
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

Between 5 to 54

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While a remote assistance session is in progress, what keyboard key(s) can the requestor press to terminate the connection?
o-na [289]

ESC key can the requestor press to terminate the connection.

<h3>what is the ESC key?</h3>
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8 0
2 years ago
বর্তমান করােনার ন্যায় পরিস্থিতি অর্থাৎ স্বাভাবিক শ্রেণি কার্যক্রম পরিচালনা সম্ভব
Zarrin [17]

Answer:

ayo fam

Explanation:

I dont think this is supposed to be here lol

5 0
3 years ago
Read 2 more answers
What general strategies can the network managers use to reduce congestions?
Harrizon [31]

Answer:

 There are different types of strategies that can be used by the network manager for reducing the congestion are as follows:

  • By monitoring the traffic of the network properly we can easily reduce the congestion in the network.
  • By segmenting the network properly, it helps to reduce the network congestion.
  • We can also reconfiguring the TCP/IP (Transmission control protocol) setting on the network.
  • We can also use the backpressure routing technique.

7 0
3 years ago
A teacher has five students who have taken four tests. The teacher uses the following grading scale to assign a letter grade to
AlladinOne [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

const int numofStudents = 5;//number of students

const int numofTests = 2;//number of tests taken by students

const int grade = 5;//number of grades available

char letter[grade] = { 'A','B','C','D','F' };

double table[numofStudents][numofTests];//defining 2darray with names and scores

string names[numofStudents];//storing names of students

for (int num = 0; num < numofStudents; num++)//storing names and scores of students

{

 cout << "Enter student's name: ";

 cin >> names[num];

 for (int test = 0; test < numofTests; test++)//scores loop

 {

  cout << "Enter the test score: ";

  cin >> table[num][test];

  if (table[num][test] < 0 || table[num][test]>100)//input validation

  {

   cout << "Invalid input. Try again" << endl;

   cin >> table[num][test];//input again

  }

 }

}

for (int i = 0;i < numofStudents;i++)//calculating averages and grades

{

 int sum = 0;

 cout << "Test scores for " << names[i] << ": " << endl;

 for (int j = 0;j < numofTests;j++)

 {

  cout << table[i][j] << " ";

  sum += table[i][j];//summing scores

 }

 cout << endl;

 float average = (float)sum / numofTests;//calculating the average

 cout << "Making an average of: "<< average;

 if (average <= 100 && average >= 90)//assigning a grade

 {

  cout << " and has received an " << letter[0];

 }

 else if (average <= 89 && average >= 80)

 {

  cout << " and has received a " << letter[1];

 }

 else if (average <= 79 && average >= 70)

 {

  cout << " and has received a " << letter[2];

 }

 else if (average <= 69 && average >= 60)

 {

  cout << " and has received a " << letter[3];

 }

 else if (average <= 59 && average >= 0)

 {

  cout << " and has received an " << letter[4];

 }

 else

 {

  cout << "Invalid scores entered." << endl;

 }

 cout << endl;

}

 return 0;

}

Explanation:

We first define the number of students, number of tests and number of grades available for assignments. We then fill in the 2D array of students names and their scores making sure assigning more than 100 and less than 0 is not allowed. We then sum the scores and retrieve an average. Using the average, a letter grade is assigned to that individual.

6 0
3 years ago
Suppose a program takes 1000 machine instructions to run from start to end, and can do that in 10 microseconds when no page faul
Tema [17]

Answer:

(10^6 + 9.9)

Explanation:

Given:

Total number of machine instructions = 1000

Number of page fault in 100 instructions = 1

Number of page faults in 1000 instructions = 10

Time to serve one page fault = 100 milliseconds

Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds

Number of instructions without any page fault = 1000 - 10 = 990

Time required to run 1000 instructions = 10 Microseconds

So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds

So, the total time required to run the program = (10^6 + 9.9) Microseconds

3 0
4 years ago
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