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3 years ago

Given the table, find 5 solutions to the equation.

Mathematics

1 answer:

nalin [4]3 years ago

5 0

Answer:

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$

Step-by-step explanation: i will help u dw chikes

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sos heklp me

ddideddiedieodieodioedieodi djl;

تتيتتيتي ااست عحيت ايست JHCOPC D

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How would you do this???

Kobotan [32]

Answer:

8.3 L/s

Step-by-step explanation:

To find the answer you need to find the slope also known as the rate of change. When you find slope it is always change in y over change in x.

$\frac{399-150}{40-10}$

Then simplify

$\frac{249}{30}$

Then divide to get your slope/average rate of change

$\frac{249}{30}$ = 8.3

6 0

4 years ago

CAN I PLSS GET HELP ASAP!!? What slope- intercept form equation represents the line

jasenka [17]

Answer:

y=-.5x+4

Step-by-step explanation:

7 0

3 years ago

Consider the inequality -5(x+7)<-10 Write an inequality representing the solution for x

Naddik [55]

-5(x+7)<-10
-5x-35<-10
+35. +35
-4x<25
both divided by-4
x> -6.25
i flipped the sign because I divided with a negative number. and I hope you can make -6.25 into a fraction, I can't because I don't have a calculator with me :(

7 0

3 years ago

Hi need help for this maths question

Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

$\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}$

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

$\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}$

c) The mean is given by the integral,

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy$

Integrate by parts, with

$u = y \implies du = dy$

$dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}$

Then

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)$

$\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy$

$\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}$

8 0

2 years ago

Identify whether the following variables are categorical or numerical. If they are numerical, then identify

Wewaii [24]

Answer:

The answers are given below in tabular form.

Step-by-step explanation:

We can prepare the following table -

Name of the variable Type If numerical discrete or

continuous

a)My favourite

ice-cream Categorical

b)The height of

basketball players Numerical Continuous

c)The time I fall

asleep at night Numerical Continuous

d)My most watched

T.V. show Categorical

e) The amount I spend

on food weekly Numerical Discrete

f) The temperature

outside Numerical Continuous

g)The no. of shoes

in my closet Numerical Discrete

6 0

3 years ago