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2 years ago

What additional piece of information is needed to prove the triangles congruent by ASA?

Mathematics

1 answer:

Iteru [2.4K]2 years ago

8 0

Another angle is needed, you only have 1 angle from each and 1 side from each whereas ASA needs 2 angles

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I got a bunch of questions under my account if someone just wants to do some work

Sliva [168]

Answer:

Alr

Step-by-step explanation:

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3 years ago

What is the value of n in the relationship 8n+9=-n+5

vitfil [10]

Subtract 5 from both sides.

$8n + 4 = -n$

Subtract 8n from both sides.

$4 = -9n$

Divide both sides by -9 to solve for n.

$- \frac{4}{9} = n$

The value of n is -4/9.

8 0

3 years ago

Find the value of n if (81)^5/n = 243

zavuch27 [327]

Answer:

N = 14348907

Step-by-step explanation:

81^5 = 3486784401

3486784401/243 = 14348907

Double Check

3486784401 / 14348907=243

So N = 14348907.

3 0

3 years ago

P(x)=(x-2)(x-4)(x-5)

Cerrena [4.2K]

The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

So, we have:

<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

$Constant = -2 \times -4 \times -5$

$Constant = -40$

Hence, the constant is -40

<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>

$Constant = -2 \times -4 \times 5$

$Constant = 40$

Hence, the constant is 40

<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>

$Constant = \frac 12 \times -2 \times -4 \times 5$

$Constant = 20$

Hence, the constant is 20

<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

$Constant = 5 \times -2 \times -4 \times 5$

$Constant = 200$

Hence, the constant is 200

$Constant = -5 \times -2 \times -4 \times 5$

$Constant = -200$

Hence, the constant is -200