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svlad2 [7]
3 years ago
8

A person came to work at 8:30 am, went out at 11:45 am, had lunch, came in at 12:30 pm, and left at 5:15 pm. How many hours did

this person work?
Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

8 hours

Step-by-step explanation:

A person came to work by 8:30 am

He went out to lunch 11:45 am and came back 12:30 pm

He closed 5:15 pm

Therefore the total hours worked that day can be calculated as follows

Time worked from 8:30 am to 11:45 am is 3 hours 15 mins

Time worked for 12:30 pm to 5:15 pm is 4 hours 45 mins

3 hours 15 mins + 4 hours 45 mins

= 8 hours

Hence the total hours worked that day is 8 hours

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Calculate the volume of the cylinder in square feet.
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3.14•4•6
3.14•24


Then multiply by 62.5 lbs/ft^2
3.14•24•62.5
3 0
2 years ago
What is 1 divided by 5^-2? Please give clear explanation. thanks.
Pani-rosa [81]
1 / 5^-2

First, let's work out the denominator.
5^ -2 = 1/25. When an exponent is negative, it means to put a 1 over the product. Like we did earlier.

Now we have 1 / (1/25). 

1 / (1/25)
Divide 1 by 25.
1 / 0.04
Divide 1 by 0.04
25

The answer is 25!

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2 years ago
Which expression is equivalent to 16 in exponential form?
Lunna [17]

Answer:

4 with the exponent or base of 2

Step-by-step explanation:

To get 16 in exponential form would be

4 × 4 = 16

3 0
3 years ago
How do you find the slope
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8 0
3 years ago
Read 2 more answers
Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])
Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

cos(θ + φ) = (-96/125) - (21/125)

cos(θ + φ) = -96/125 - 21/125

cos(θ + φ) = -117/125

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2 years ago
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