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Oxana [17]
3 years ago
6

What is the smallest integer that can be divided by the product of a prime number and 7 while yielding a prime number?

Mathematics
1 answer:
frozen [14]3 years ago
5 0
Short Answer 28
If I'm reading this correctly it is 28.
2 is a prime number.
7 is also a prime

They are multiplied together to give 2*7 = 14

When you divide 28/14 you get 2 which is the smallest prime. 
28 <<< Answer
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Consider the function y = x2 − 18x. Enter the values for the variables to complete the inverse.
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Step-by-step explanation:

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Step-by-step explanation:

5 0
3 years ago
Use addition to solve the linear system of equations. Include all of your work in your final answer. \(\left\{ \right.\) 3x-y=6
ad-work [718]

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

3x-y=6 \\y=x-4

We can write second equation y=x-4  as: -x+y=-4

Let:

3x-y=6--eq(1)\\ -x+y=-4--eq(2)

Now, Adding equation 1 and 2

3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1

So, we get x = 1

Now, put value of x in second equation to find value of y:

y=x-4\\Put\:x=1\\y=1-4\\y=-3

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0
3 years ago
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