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Oxana [17]
4 years ago
6

What is the smallest integer that can be divided by the product of a prime number and 7 while yielding a prime number?

Mathematics
1 answer:
frozen [14]4 years ago
5 0
Short Answer 28
If I'm reading this correctly it is 28.
2 is a prime number.
7 is also a prime

They are multiplied together to give 2*7 = 14

When you divide 28/14 you get 2 which is the smallest prime. 
28 <<< Answer
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Write the expression in radical form.
kvv77 [185]
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Explanation:
7 0
3 years ago
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What is the product?<br> (X^4) (3x^3-2)(4x^2+5x)?
Allisa [31]

(x^4)(3x^3-2)(4x^2+5x)

=(3x^7-2x^4)(4x^2+5x)

=12x^9+15x^8-8x^6-10x^5

answer: 12x^9+15x^8-8x^6-10x^5

8 0
3 years ago
Last one - Thank you an advance :)
Ivan
Answers:
a. Given
b. Transitive property of congruence
c. Vertical angles are congruent
d. Transitive property of congruence

Let me know if you need any clarification as to how I got those answers. They should be self-explanatory but I'm happy to clarify further if needed. 

5 0
3 years ago
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Solve.<br><br><br><br> −3(n + 8) = 15<br><br><br><br> The solution is n = <br><br> .
Vladimir [108]
First, we can do distributive property.

-3(n + 8) = 15

-3 x n = -3n, -3 x 8 = -24 

So we have, -3n + -24 = 15
 
Minus -24 on both sides of the equal sign.

-3n + -24 - -24 = 15 - -24 

-3n = 39

Divide 3 on both sides.

-3n/-3 = 39/-3

n = -13

Hope i helped!! :D
5 0
3 years ago
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