All categories

3 years ago

Solve. −3(n + 8) = 15 The solution is n = .

2 answers:

5 0

First, we can do distributive property.

-3(n + 8) = 15

-3 x n = -3n, -3 x 8 = -24

So we have, -3n + -24 = 15

Minus -24 on both sides of the equal sign.

-3n + -24 - -24 = 15 - -24

-3n = 39

Divide 3 on both sides.

-3n/-3 = 39/-3

n = -13

Hope i helped!! :D

Svetllana [295]3 years ago

5 0

-3(n + 8) = 15
-3n - 24 = 15
-3n = 15 + 24
-3n = 39
n = 39/-3
n = -13

You might be interested in

two golfers completed one round of golf. the first golfer had a score of +6 and the second golfer had a score of -3. how many mo

pav-90 [236]

9. One is 6 over par, the other is three under, so subtract first-second = 6-(-3) = 9

4 0

4 years ago

Someone answer 1-8 please! (Please do help!)<br> QUESTION: Find each quotient.

Zinaida [17]

Sorry, but I generally respond to only 1 or 2 problems when someone gives me a long list of homework. It would take you just a little longer to post one problem at a time.
75 5 -375
Let's look at #5: 75 / (-1/5) is the same as -------- = 75 * ------ = --------- -1 -1 1
---
5

and this is equivalent to -375 (answer to #5)

6 0

4 years ago

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

3 years ago

With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the

coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is $1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day$

The median is $Median = 38 ^{th} \ girl (subject) = 2 \serving\ of\ fruit\ per\ day$

The third quartile is $3rd Q = 56^{th} \ girl (subject) = 4 \serving\ of\ fruit\ per\ day$

The mean is $\= x = 2.62$

Step-by-step explanation:

From the question we are told that

The total number of girls is n = 74

Generally the median is mathematically represented as

$Median = \frac{\frac{n}{2} +[ \frac{n}{2} + 1] }{2}$

$Median = \frac{\frac{74}{2} +[ \frac{74}{2} + 1] }{2}$

=> $Median = \frac{37 +38 }{2}$

=> $Median =37.5 \ girl$

From the histogram $37.5 \approx 38^{th} \ girl$ fall under 2 fruits per day

Generally the first quartile is mathematically represented as

$1st \ Q = \frac{\frac{n}{4} + [\frac{n}{4} + 1] }{2}$

=> $1st \ Q = \frac{\frac{74}{4} + [\frac{74}{4} + 1] }{2}$

=> $1st \ Q = 19 \ girl$

From the histogram $19^{th}$ girl fall under 1 fruit per day

Generally the third quartile is mathematically represented as

$3rd\ Q = \frac{\frac{n}{2} + n }{2}$

=> $3rd\ Q = \frac{\frac{74}{2} + 74 }{2}$

=> $3rd\ Q = 55.5$

From the histogram $55.5 \approx 56^{th} \ girl$ fall under 4 fruits per day

Generally from the histogram table the frequency [number of subjects (girls) ] and the servings of fruit per day can be represented as

Total

x(servings per day ) 0 1 2 3 4 5 6 7 8

f (number of subjects ) 15 11 15 11 8 5 3 3 3 $\sum f = 74$

xf 0 11 30 33 32 25 18 21 24 $\sum xf = 194$

Generally the mean is mathematically represented as

$\= x = \frac{1}{ \sum f} * [\sum xf]$

=> $\= x = \frac{1}{ 74} *194$

=> $\= x = 2.62$

4 0

3 years ago

Which shape is a rectangle

Nezavi [6.7K]

Answer:

Top left.

Step-by-step explanation:

Definition of a rectangle:

A four sided figure with 90 degree angles. The opposing side pairs are congruent with each other. It's the equivalent of a modified, upgraded parallelogram.

Now, the square is the answer since it fits all of the criteria of the rectangle, with the addition of having four congruent sides.

8 0

3 years ago

Read 2 more answers