Answer:
.
Step-by-step explanation:
.
Answer:
Julie weighs 35 lbs, Ted weighs 70 lbs, Mike weighs 105 lbs.
Step-by-step explanation:
Let the weight of Julie be ![x](https://tex.z-dn.net/?f=x)
Given:
Ted weighs twice as much as Julie
Weight of Ted = ![2x](https://tex.z-dn.net/?f=2x)
Mike weighs three times as much as Julie.
Weight of Mike = ![3x](https://tex.z-dn.net/?f=3x)
Together, Ted, Mike, and Julie weigh 210 lbs.
![x+2x+3x=210](https://tex.z-dn.net/?f=x%2B2x%2B3x%3D210)
Solving above we get;
![6x=210\\x=\frac{210}{6}=35\ lbs](https://tex.z-dn.net/?f=6x%3D210%5C%5Cx%3D%5Cfrac%7B210%7D%7B6%7D%3D35%5C%20lbs)
Hence Julie weight is 35 lbs.
Weight of Ted = ![2x=2\times 35 = 70 \ lbs](https://tex.z-dn.net/?f=2x%3D2%5Ctimes%2035%20%3D%2070%20%5C%20lbs)
Hence Ted weight is 70 lbs.
Weight of Mike = ![3x=3\times 35 = 105 \ lbs](https://tex.z-dn.net/?f=3x%3D3%5Ctimes%2035%20%3D%20105%20%5C%20lbs)
Hence Mike weight is 105 lbs.
True because of 15 and 20
13 : 2/100 = 13 * 100/2 = 13 * 50 = 650
Answer: Its 1
Step-by-step explanation: