Separate into two groups
y^3(5y+4) + 5(5y+4)
(y^3 + 5)(5y + 4)
4 + 2h < -3
2h < -7
h < -3.5
x ∈ (-∞, -3.5)
Given that AB = 16, BC = 5, and CD = 3, which is the length of secant DE?It might be useful to see ...
If the -1 is not included, then your answer is 3.17.
2(3x-4)=11
3x2=6 and -4x2= -8
6x-8=11
+8 +8
6x=19
/6 /6
X= 3.17
