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Fed [463]
3 years ago
10

alexander is a stockbroker 13% commission each week. Last week, he sold $6,800 worth of stocks. How much did he make last week i

n commission? If he averages that same amount each week, how much did he make in commission in 2011?
Mathematics
1 answer:
Daniel [21]3 years ago
8 0
He made $46592 in 2011
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Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
4,6,9,...<br> Find the 8th term.<br> Find the 8th term.
krek1111 [17]

Answer:

4, 6, 9, 12, 15, 18, 21, <u><em>24.</em></u>

Step-by-step explanation:

The 8th term is 24.

just +2 (add 2) every time.

3 0
2 years ago
I NEED HELP WITH THIS QUESTION PLEASE
Naddika [18.5K]
From 0 move to left two 1/3, them move to right four 1/3. The answer is 2/3
See the image

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3 years ago
Explain why (a+b)^2 = a^2+b^2 if and only if a=0 or b=0
const2013 [10]

Hope this helps! Because when you would fill in the variables 0=0 which which make the expression too that they’d equal the same.

7 0
2 years ago
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
sweet [91]
A conservative vector field \mathbf f has curl \nabla\times\mathbf f=\mathbf0. In this case,

\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0

so the vector field is not conservative.
3 0
3 years ago
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