Pls helpp!!!!!!!!!!!!!

Mathematics

1 answer:

Aleks [24]3 years ago

6 0

Answer: Yes

The point (-8,4) makes the inequality $11x + 2y \le 19$ true

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Explanation:

We have x = -8 and y = 4 pair up together due to the point (x,y) = (-8,4).

Let's plug these values into the inequality

$11x + 2y \le 19\\\\11(-8) + 2(4) \le 19\\\\-88+8 \le 19\\\\-80 \le 19\\\\$

The last inequality is true because -80 is to the left of 19 on the number line. So -80 is smaller than 19.

Since the last inequality is true, this means the first inequality is true when (x,y) = (-8,4).

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Brrunno [24]

f(x)=x²-1
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using a graph tool see the attached figure

6 0

4 years ago

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$