X + (x + 1) + (x + 2) = 126
3x = 123
x = 41
So the sides are 41, 42 and 43
Question has missing details (Full question below)
Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage
Answer:
Mean = 219
Variance = 4
Step-by-step explanation:
Given
Let X be a random variable measurement error.
X has a discrete uniform distribution as follows
a = 219 - 3 = 216
b = 219 + 3 = 222
Mean or Expected value is calculated as follows;
E(x) = ½(216+222)
E(x) = ½ * 438
E(x) = 219
Variance is calculated as follows;
Var(x) = ((b-a+1)²-1)/12
Var(x) = ((222-216+1)²-1)/12
Var(x) = (7²-1)/12
Var(x) = 48/12
Var(x) = 4
Answer:
V≈1282.82
Step-by-step explanation:
V=πr^2h
3=π·72·25
3≈1282.817
Step-by-step explanation:
a.
2(3x) - 5x = 4
6x - 5x = 4
x = 4
B. -5(x-4)+8x=29
-5x+20+8x=29
3x+20=29
3x=9
x=3
C. 2y=18+2(3-y)
2y=18+6-2y
2y=24-2y
4y=24
y=6
D. c = -b - 11
3c + 6 = 6b
3( -b - 11) +6 = 6b
-3b-33+6=6b
-3b-27=6b
-27=9b
3=b
