Given the differential equation
The solution is as follows:
Answer: No, the money won't be enough to buy the car
Step-by-step explanation:
you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.
The principal amount, p = 300
He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So
n = 4
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for a total of 24 months. This is equivalent to 2 years. So
n = 2
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount that would be compounded at the end of n years.
A = 300(1 + (0.04/4)/4)^4×2
A = 300(1 + 0.01)^8
A = 300(1.01)^8
A = $324.857
The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car
Gretchen will earn $48 from mowing in 4 hours
Data
- Amount earned on each lawn = $12
- Number of hours mowing = 4 hours
<h3>What is Rate</h3>
This is the measure of one unit against another unit. An example of this is speed which is the rate of distance covered to time.
In this case, she mows 1 lawn in each hour and earns $12 on each.
To calculate for 4 hours
She earns $48 from mowing 4 lawns
learn more on rates here;
brainly.com/question/8728504
Answer:
a) False
b) False
c) True
d) False
e) False
Step-by-step explanation:
a. A single vector by itself is linearly dependent. False
If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.
b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False
A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.
c. The columns of an invertible n × n matrix form a basis for Rⁿ. True
If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.
d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False
Row operations can not affect linear dependence among the columns of a matrix.
e. A basis is a spanning set that is as large as possible. False
A basis is not a large spanning set. A basis is the smallest spanning set.
