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3 years ago

Answer both please asap (there’s a picture)

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

7 0

Answer:

the Solution is 0,1

Step-by-step explanation:

Because the place where the two lines intersect are the two numbers that are the answer to the system.

krek1111 [17]3 years ago

4 0

Answer:

(0, 1)

Step-by-step explanation:

So, the spot on the graph where they cross.

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I have to turn this in today lol help pls:)

mrs_skeptik [129]

400, if you can buy 4 tickets for $6 you can buy 400 for $600

6 0

3 years ago

A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular

Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = $\frac{360}{8}$

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

$sin 22.5=\frac{AC}{OA}$

$=\frac{AC}{x}$

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, $cos 22.5=\frac{OC}{OA}$

$=\frac{OC}{x}$

So, OC = x cos 22.5°.

Area of Δ AOB = $\frac{1}{2}(AB)(OC)$

= $\frac{1}{2}$ × (2x sin 22.5°) × (x cos 22.5°)

= $\frac{1}{2} x^{2}$ (2 sin 22.5° cos 22.5°)

= $\frac{1}{2} x^{2}$ sin 45°

= $x^{2}$ / $2\sqrt{2}$

Area of the octagonal gazebo = 8 × one triangular area

= 8 × ( $x^{2}$ / $2\sqrt{2}$ )

$=2\sqrt{2} x^{2}$

$=2.828x^{2}$

Area required for mulch = circular area - area of the gazebo

$=3.14x^{2} -2.828x^{2}$

$=0.312x^{2}$

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = $0.312x^{2}$ × 1.5

$=0.468x^{2}$

Hence, total cost g(m) = $0.468x^{2}$ .

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7C2v%7C%20%20%3D%2012" id="TexFormula1" title=" |2v| = 12" alt=" |2v| = 12" align="absmi

BlackZzzverrR [31]

Answer:

v=6

Step-by-step explanation:

2v is positive so keep it

then 2v=12

v=6

8 0

3 years ago

Read 2 more answers

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

For Bus:

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

For motorcycle:

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago

If m<22 =122 what is m<5

Ludmilka [50]

Answer:

m = -5

Step-by-step explanation:

Step 1 :

Pulling out like terms/ factors

Add 5 to both sides of the equation :

-m = 5

Multiply both sides of the equation by (-1) : m = -5

Hope this helps.

5 0

3 years ago