[tex}r - 5 \frac{5}6 + 5\frac{5}6 = 10 +5\frac{5}6{/tex]
Determine the Equation of the line Perpendicular to 2x -3y +5= 0 and passers through (-6,-3)
1 answer:
9514 1404 393
Answer:
3x +2y +24 = 0
Step-by-step explanation:
In general, the equation of a perpendicular line can be found by swapping the coefficients of x and y, then negating one of them. The value of the constant will be what is required to make the line pass through the given point.
The equation will be of the form ...
3x +2y +c = 0
At the given point, (x, y) = (-6, -3), we have ...
3(-6) +2(-3) +c = 0 . . . . substitute the given point coordinates
-18 -6 +c = 0 . . .simplify
c = 24 . . . . . . . . add 24
The general-form equation for the line is ...
3x +2y +24 = 0 . . . . . shown in blue in the attachment
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Answer:
A.
mean = 724.2
Median = 715
Mode = 768
B.
Range = 85
Standard deviation = 29.30
C.
Interval = [665.6, 782.8]
Step-by-step explanation:
Number of samples n = 25
Summation X= 769 + 691 + 699 +730+711+ 765+ 702 718 +719 +712+ 768 +688 +757+695 768 +735 +709 +758 +708+ 693 +736 700+ 687 +772 +715 = 18105
A.
1. Mean = 18105/25
= 724.2
2. Median is the middle value when arranged from the least value to the highest = 715
3. Mode is the number with the highest frequency = 768 (occured two times)
B.
1. Range = highest value - lowest value
Highest value = 772
Lowest value = 687
772-687 = 85
2. Standard deviation = √(X-barX)²/n-1
= √20604/25-1
=√858.5
= 29.30
Please check attachment for the full calculation of the standard deviation
C.
Interval
[Mean - 2(sd), mean + 2(sd)]
= [724.2-2x29.3, 724.2+2x29.3]
=[665.6, 782.8]
