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sergey [27]
3 years ago
5

7h + 3 = 7(2+h) -11 this is my question

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

Step-by-step explanation:

7h+3=7(2+h)-11

7h+3=14+7h-11

7h+3=7h+3

The answer is 0 or no solution since they cancel each other out.

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Rose bought a bag of potatoes for $6.00 and some granola bars for $5.25 per package. Her total bill was $74.25. How many package
neonofarm [45]

Answer:

Rose bought 14 packages of granola bars.

Step-by-step explanation:

Total bill = 1 bag of potatoes + x amount of packages of granola bars

Total bill = $74.25

1 bag of potatoes = $6.00

1 package of granola bar = 5.25

We set the equation to:

74.25 = 6.00 + 5.25x

Subtract 6.00 from both sides:

68.25 = 5.25x

Divide both sides by 5.25 to leave x by itself

68.25/5.25 = 5.25x/5.25

13 = x

This means Rose bought 13 packages of granola bars.

Let's recheck our work by inputting x = 13 into the equation:

74.25 = 6.00 + 5.25(13)

74.25 = 6.00 + 68.25

74.25 = 74.25

7 0
2 years ago
Simplify the product using FOIL. (4x + 3)(2x + 5)
Dafna1 [17]
8x^2+20x+6x+15. Combine like terms. 8x^2+26x+15. When using foil just multiply the contents of one pair of brackets on another pair.
3 0
3 years ago
Read 2 more answers
PLLLEASEEE HELLPPP I WILL GIVE BRAINLIEST!!!!
vesna_86 [32]

Answer:

Step-by-step explanation:

to make it quick

2*110 = arc FI

220° = arc FI

arc LI = 97°

arc FL = x

360 = 220 + 97 + x

43 = X

arc FL = 43°

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4 0
3 years ago
A flower pot’s base has six sides that are all the same length. Each side measures x−6 units. The base’s perimeter is 78 units.
torisob [31]
6(x-6)=78
6x-36=78
6x-36+36=78+36
6x=114
6x÷6=114÷6
x=19
6 0
3 years ago
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Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
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