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anzhelika [568]
3 years ago
13

Help me out here please???

Chemistry
2 answers:
san4es73 [151]3 years ago
5 0

Answer:

A

Explanation:

WARRIOR [948]3 years ago
3 0

Answer:

B

Explanation:

In a chemical reaction, the number of each element should be equal on both the reactant and product side.

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noname [10]

Answer:

the third one because oceans don't affect the weather  

Explanation:

7 0
3 years ago
Balance the following reaction. If a coefficient of "1" is required, choose "blank" for that box. C4H8 + Br2 → C4H8Br2
DENIUS [597]

Answer:

C₄H₈ + Br₂ → C₄H₈Br₂

Explanation:

To balance a chemical equation, you need to ensure that the number of each element in the reactant side, matches the number of each element on the product side.

 Reactants                   Product

C₄H₈ + Br₂         →          C₄H₈Br₂

C = 4                                 C= 4

H = 8                                 H= 8

Br = 2                                Br = 2

Since they match up on both sides, the chemical equation is balanced, so we keep it as is.

6 0
3 years ago
brina thinks dissolvung more salt in water cause the mixture freezing temperature to chang which is the best type of sciectific
ddd [48]

put some water out with less salt and then some more water out with more salt and look at the differences with the freezing.

7 0
4 years ago
The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
Vinil7 [7]

Answer:

Here's what I get  

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}

3. Check:

Compare the final concentration with the original

\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}

7 0
3 years ago
You have 56.8 mL of a gas collected at 664 mmHg and 135 K. What volume will it occupy at 632 mmHg and 196 K? *
tensa zangetsu [6.8K]

Answer:

86.6 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 56.8 mL

Initial pressure (P₁) = 664 mmHg

Initial temperature (T₁) = 135 K

Final pressure (P₂) = 632 mmHg

Final temperature (T₂) = 196 K

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

664 × 56.8 / 135 = 632 × V₂ / 196

Cross multiply

135 × 632 × V₂ = 664 × 56.8 × 196

85320 × V₂ = 7392179.2

Divide both side by 85320

V₂ = 7392179.2 / 85320

V₂ = 86.6 mL

Therefore, the final volume of the gas is 86.6 mL

5 0
3 years ago
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