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dangina [55]
3 years ago
10

Solve this: -11<-x+2<8. ?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
You add 2 to each of the three sides.

okay?

-11< -x+2< 8
-2 -2 -2
--------------------
-13< -x <2
Divide by negative 1

-13< -x <2
--------------
-1
Switch the signs direction

13> x > -2

tada
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You should draw a line of best fit for a scatter plot if there is no correlation among the data points. True False
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False

Step-by-step explanation:

N/A

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3 years ago
Hilda adds 5 to a number, then multiples the sum by -2. The result is 6. Write and equation to find the number, x. What is the n
Novay_Z [31]

(x+5)*(-2) = 6

distribute

-2x -10 = 6

add 10 to each side

-2x -10 +10 = 6+10

-2x = 16

divide by -2

-2x/-2 = 16/-2

x = -8

The number is -8

3 0
3 years ago
2.5x + 11 = 50 can you give me the answer plz HELP
Wewaii [24]

Answer:

X= 15.6

Step-by-step explanation:

Hope it was helpful ;)

8 0
3 years ago
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During a storm, rain fell at a rate of 0.25
Hoochie [10]

Answer:

1.5

Step-by-step explanation:

You would multiply 0.25 times the 6 hours.

0.25 x 6= 1.5

6 0
3 years ago
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The life of light bulbs is distributed normally. the variance of the lifetime is 625 and the mean lifetime of a bulb is 530 hour
goldfiish [28.3K]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>What is Normal Probability Distribution?</h3>

The z-score of a measure X of a normally distributed variable with mean  and standard deviation  is given by:

z =\dfrac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 530  \sigma^2 = 625 \sigma = 25

The probability of a bulb lasting for at most 569 hours is the p-value of Z when X = 569, hence:

z =\dfrac{X - \mu}{\sigma}

z = \dfrac{564 -530}{25} = 1.36

Z = 1.36 has a p-value of 0.9131

0.9131 x  100 = 91.31 % probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

3 0
2 years ago
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