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4 years ago

What's the fraction for 2%

Mathematics

2 answers:

olga55 [171]4 years ago

8 0

= 2%
= 0.02 
= 2/100
= 1/50

SO, 2% = 1/50

Hope I helped:P

tamaranim1 [39]4 years ago

4 0

Changing percent to fraction is an easy thing.
Here is how:
1. Simply put the given number over 100. (Let us have 2%). Drop the percent sign.
 2% becomes 2 
 100
2. Reduce the fraction into its lowest term.
 In reducing its lowest term, we should find their GCF first as their divisor.
 2 = 1, 2
 100 = 1, 2, 4, 5, 10, 20, 25, 50, 100
 Their Greatest Common Factor (GCF) is 2.
3. Divide evenly.
 2 ÷ 2 = 1 
100 2 50

So, 2% is 1/50 when changed into fraction.

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QUESTIONS The average price of wheat per metric ton in 2012 was $30575. Demand in millions of metric tons) in 2012 was 672. The

soldi70 [24.7K]

Answer: -0.9 ; inelastic

Explanation:

Given:

The average price of wheat per metric ton in 2012 = $305.75

Demand (in millions of metric tons) in 2012 = 672

The average price of wheat per metric ton in 2013 = $291.56

Demand (in millions of metric tons) in 2013 = 700

We will compute the elasticity using the following formula:

ε = $\frac{\frac{(Q_{2} - Q_{1})}{\frac{(Q_{2} +Q_{1})}{2}}}{\frac{(P_{2} - P_{1})}{\frac{(P_{2} +P_{1})}{2}}}$

ε = $\frac{\Delta Q}{\Delta P}$

Now , we'll first compute $\Delta Q$

i.e. $\frac{\Delta Q}{\Delta P}$ = $\frac{(700 - 672)}{\frac{(700 +672)}{2}}$

$\Delta Q$ = 0.04081

Similarly for $\Delta P$

i.e. $\Delta P$ = $\frac{(291.56 - 305.75)}{\frac{(261.56 +305.75)}{2}}$

$\Delta P$ = -0.0475

ε = $\frac{0.04081}{-0.0475}$

ε = -0.859 $\simeq$ -0.9

$\because$ we know that ;

If, ε > 1 ⇒ Elastic

ε < 1 ⇒ Inelastic

ε = 1 ⇒ unit elastic

$\because$ Here , ε = -0.859 $\simeq$ -0.9

Therefore ε is inelastic.

6 0

4 years ago

ANSWER ASAP PLEASE! WILL GIVE BRAINLIEST, RATING, AND THANKS!

vladimir2022 [97]

she is incorrect the numbers listed above is neither arithmetic or geometric its quadratic sequence . its addition being shown

2+1=3

3+2=5

5+3=8

8+4=12

hope i broke it down enough for you're understanding

8 0

4 years ago

Read 2 more answers

Let C be the curve of intersection of the parabolic cylinder x^2 = 2y, and the surface 3z = xy. Find the exact length of C from

Maslowich

I've attached a plot of the intersection (highlighted in red) between the parabolic cylinder (orange) and the hyperbolic paraboloid (blue).

The arc length can be computed with a line integral, but first we'll need a parameterization for $C$ . This is easy enough to do. First fix any one variable. For convenience, choose $x$ .

Now, $x^2=2y\implies y=\dfrac{x^2}2$ , and $3z=xy\implies z=\dfrac{x^3}6$ . The intersection is thus parameterized by the vector-valued function

$\mathbf r(x)=\left\langle x,\dfrac{x^2}2,\dfrac{x^3}6\right\rangle$

where $0\le x\le 4$ . The arc length is computed with the integral

$\displaystyle\int_C\mathrm dS=\int_0^4\|\mathbf r'(x)\|\,\mathrm dx=\int_0^4\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}\,\mathrm dx$

Some rewriting:

$\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}=\sqrt{\dfrac{x^2}{36}}\sqrt{x^4+9x^2+36}=\dfrac x6\sqrt{x^4+9x^2+36}$

Complete the square to get

$x^4+9x^2+36=\left(x^2+\dfrac92\right)^2+\dfrac{63}4$

So in the integral, you can substitute $y=x^2+\dfrac92$ to get

$\displaystyle\frac16\int_0^4x\sqrt{\left(x^2+\frac92\right)^2+\frac{63}4}\,\mathrm dx=\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy$

Next substitute $y=\dfrac{\sqrt{63}}2\tan z$ , so that the integral becomes

$\displaystyle\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy=\frac{21}{16}\int_{\arctan(3/\sqrt7)}^{\arctan(41/(3\sqrt7))}\sec^3z\,\mathrm dz$

This is a fairly standard integral (it even has its own Wiki page, if you're not familiar with the derivation):

$\displaystyle\int\sec^3z\,\mathrm dz=\frac12\sec z\tan z+\frac12\ln|\sec x+\tan x|+C$

So the arc length is

$\displaystyle\frac{21}{32}\left(\sec z\tan z+\ln|\sec x+\tan x|\right)\bigg|_{z=\arctan(3/\sqrt7)}^{z=\arctan(41/(3\sqrt7))}=\frac{21}{32}\ln\left(\frac{41+4\sqrt{109}}{21}\right)+\frac{41\sqrt{109}}{24}-\frac98$