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gizmo_the_mogwai [7]
3 years ago
8

Is the piecewise graph a function? check using the vertical line test.​

Mathematics
1 answer:
Blababa [14]3 years ago
4 0

Answer:

No

General Formulas and Concepts:

  • Vertical Line Test

Step-by-step explanation:

When we apply the VLT, we see that when x = -2 and -1, that the VLT fails. Therefore, it is NOT a function.

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What is the solution (x,y) to the system of equations given? 2 x + 4 y = − 16 2x+4y=−16 2 y − x = = 16 2y−x==16
alisha [4.7K]

Answer:

(-12,2)

Step-by-step explanation:

2x + 4y = -16

2y - x = 16

Multiply the bottom part by 2.

2x + 4y = -16

4y - 2x = 32

Add the equations and the answers to the equations up, and they will equal each other.

(2x + 4y) + (4y - 2x) = -16 + 32

8y = 16

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3 0
4 years ago
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
4 years ago
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