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Sedbober [7]
3 years ago
15

A cement path consists of six equal-sized cement squares arranged in a row to form a rectangle. If the total area of the path is

96 square feet, what is the length in feet of the path?
Mathematics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

24 feet

Step-by-step explanation:

Given that:

The length of the rectangle is 6 times the side of a cement square.

Now, this rectangle is formed from 6 squares;

The total area of the path of this square = 96 square feet;

The area of each square now = 96/6 = 16 square feet

Recall that:

Area of a square = S²

where S is the side length

16 = S²

S = \sqrt{16}

S = 4 ft

The length of the path in feet now is: L × w

= 6 × 4

= 24 feet.

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Chi would have two thousand nickels because if 100 nickels is 5% and 100 divided 5 is 20 so a 100 times 20 is 2000
3 0
2 years ago
0.05 in scientific notation
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As a matter of fact, the coefficient should be ≥ 1 and < 10.

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Hope this helps~
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2 years ago
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Whats the MIDPOINT of (2, 4) and (1, -3)
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The midpoint is (3/2 , 1/2) .
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3 years ago
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A ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by
german

Step-by-step explanation:

A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :

f(t) = -32 t+285

Height of the ball is :

h(t)=\int\limits{f(t){\cdot} dt}\\\\h(t)=\int\limits{(-32t+285){\cdot} dt}\\\\h(t)=-16t^2+285t+C

C is constant. Here the ball is launched from a height of 6 feet. So,

h(t)=-16t^2+285t+6

At t = 2 s, h(t)=-16(2)^2+285(2)+6=512\ m

At t = 9 s, h(t)=-16(9)^2+285(9)+6=1275\ m

Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.

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3 years ago
SOLVE CORRECTLY AND SHOW WORKKKK!
nadya68 [22]

Answer:

50=(3x)x

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