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2 years ago

One side of a regular hexagon is 18 cm. which is the perimeter

2 answers:

8 0

"Hexagon" means it has six sides.
"Regular" means all of its sides are the same length.

So the perimeter of a regular hexagon is (6) times (the length of any side).

6 x 18 cm = <em>108 cm</em>

mel-nik [20]2 years ago

6 0

6 sides to a hexagon
if one side is 18 cm, then you can solve this by creating the equation:
18*6=108
the perimeter is 108 cm

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PLEASE HELP

Usimov [2.4K]

Answer:

$r\approx0.03\text{ or about $3\%$}$

Step-by-step explanation:

The standard compound interest formula is given by:

$\displaystyle A=P(1+\frac{r}{n})^{nt}$

Where A is the amount afterwards, P is the principal, r is the rate, n is the times compounded per year, and t is the number of years.

Since we are compounding annually, n=1. Therefore:

$\displaystyle A = P (1+r)^{t}$

Lester wants to invest $10,000. So, P=10,000.

He wants to earn $1000 interest. Therefore, our final amount should be 11000. So, A=11000.

And our timeframe is 3.3 years. So, t=3.3. Substituting these values, we get:

$11000=10000(1+r)^{3.3}$

Let’s solve for our rate r.

Divide both sides by 10000:

$1.1=(1+r)^{3.3}$

We can raise both sides to 1/3.3. So:

$\displaystyle (1.1)^\frac{1}{3.3}=((1+r)^{3.3})^\frac{1}{3.3}$

The right side will cancel:

$\displaystyle r+1=(1.1)^\frac{1}{3.3}$

So:

$\displaystyle r=(1.1)^\frac{1}{3.3}-1$

Use a calculator:

$r\approx0.03$

So, the annual rate of interest needs to be about 0.03 or 3% in order for Lester to earn his interest.

5 0

2 years ago

There are many ways to measure the reading ability of children. Research designed to improve reading performance is dependent on

ELEN [110]

Answer:

A 90% confidence interval to estimate the mean DRP score in Henrico County Schools is =32±2.7280

i.e. C.I. [29.3,34.7]

Hence the results are not significant.

Step-by-step explanation:

Given:

Total no of students =44

True mean =32

Standard deviation=11

And all 4 students score also given.

To Find:

90 % confidence interval and conclusion on it.

Solution:

Here for C.I. we required mean, standard deviation and no of students.

So mean =32,S.D.=11 and n=44

Therefore , For 90 % interval Zscore is Z=1.645

C.I.=mean±Z[Standard deviation/Sqrt(n)]

=32±1.645[11/Sqrt(44)]

=32±1.645[1.6583]

=32±2.7280

i.e. C.I. [29.3,34.7]

Now Here to commit on calculated interval we should check value of Z-score

So we need to calculate the sample mean.

Sample mean =Sum of all values /Total no of values.

=[40+ 26 +39+ 14+ 42+ 18 +25+ 43+ 46 +27 +19+ 47+ 19 +26+ 35 +34+ 15+ 44 40+ 38+ 31+ 46 +52 +25+ 35 +35+ 33 +29 +34 +41 +49+ 28+ 42+ 47 +35 +48 +22 33+ 41 +51 +27 +14+ 54 +45]/44

=34.86

Z-score=(sample mean -true mean)/[standard deviation/Sqrt(n)]

=(34.86-32)/[11/Sqrt(44)]

Z=1.72465

For ,

P(Z≥1.72465)=0.08544

For 0.05 significance level the results are not significant at p<0.01.

Researcher claimed mean is not correct upto 0.05 significant level

i.e calculated mean and Sample mean are different.

Hence the results are not significant.

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2 years ago

2 ( −14 + r ) − ( −3r − 5 )

svet-max [94.6K]

-28+2r+3r+5
simplified it is -23+5r

4 0

3 years ago

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Divide 1/3 yd by 9/13 ? please show work

babunello [35]

Answer:

13/27

Step-by-step explanation:

1/3 ÷ 9/13

Copy dot flip

1/3 * 13/9

13/27

5 0

3 years ago

In the below system, solve for y in the first equation.

fiasKO [112]

The correct answer should be A.

4 0

3 years ago

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