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3 years ago

"Find the missing side. Round to the nearest tenth when necessary.

Mathematics

2 answers:

White raven [17]3 years ago

6 0

By using the pythogrean theorem

root 18^2-9^2 = 15.58 ~ 15.6

Allushta [10]3 years ago

3 0

Answer:

15.6

Step-by-step explanation:

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A craft store buys 50 yards of satin ribon for $12.50. The store sells the ribbon by the foot. A customer can purchase 5 feet of

amm1812

Answer:

$8.1

Step-by-step explanation:

Convert 45 yards of ribbon to feet through proper conversion factor.

(45 yards)(3 ft / 1 yard) = 135 feet

Divide this number by 5 to determine the number of 5-ft ribbon that customers can purchased.

n = 135 ft / 5 ft = 27

Then, multiply by $0.80.

R = (27)($0.80) = $21.6

The profit is equal to $21.6 and $13.50,

P = $21.6 - $13.50 = $8.1

Answer: $8.1

8 0

3 years ago

find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it. Use 3.14 as an

skad [1K]

Answer:

2794 m^2

Step-by-step explanation:

Area of Triangle - Area of Circle

1/2bh - piR^2

4050 - 1256

= 2794

3 0

3 years ago

3 ( 2m - 1 ) - 5m ≤ -1 Please help

Rudiy27

3 ( 2m - 1 ) - 5m ≤ -1

6m-3-5m≤ -1

m-3≤ -1

m ≤ 2

6 0

3 years ago

Read 2 more answers

If you have 2 cups of flour, 2 pints of milk, and 2#'s of heavy cream; what is the total weight in #'s. that you have?

BARSIC [14]

Answer:6

2+2+2=6

I hope it helps :)

8 0

2 years ago

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. Wh

leonid [27]

Answer:

The maximum height of the particle is 100 ft

A is correct

Step-by-step explanation:

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.

The standard equation of parabolic projectile.

$h(t)=-16t^2+v_0t+h_0$

where,

$v_0=16\ ft/s$

$h_0=96\ ft$

$h(t)=-16t^2+16t+96$

So, we get the parabolic equation of path.

The maximum value at vertex.

$t=-\dfrac{b}{2a}$

$t=-\dfrac{16}{-32}=\dfrac{1}{2}$

Maximum at t=0.5

$h(0.5)=-16(0.5)^2+16(0.5)+96$

$h(0.5)=100$

Hence, The maximum height of the particle is 100 ft

4 0

3 years ago

Read 2 more answers