Question

Please help asap! Easy question :)

Answer 1

Answer:

P(​one number is a multiple of 4 and the other is a multiple of 6) = 1/18

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Total outcomes:

For the pair of dice:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

So 36 total outcomes.

Desired outcomes:

One multiple of 4 and one multiple of 6.

2 possible outcomes: (4,6) or (6,4)

Probability:

2 outcomes out of 36, so:

$p = \frac{2}{36} = \frac{1}{18}$

Then

P(​one number is a multiple of 4 and the other is a multiple of 6) = 1/18