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3 years ago

A swimming pool has a rectangular base 10 ft long and 20 ft wide. The sides are 4 ft high, and the pool is half

Mathematics

1 answer:

Lostsunrise [7]3 years ago

7 0

Answer:74880 ft.lb

Step-by-step explanation:

Given

Dimension of pool

base=10 ft

width=20 ft

height=4 ft

Pool is half filled

volume of Pool $=10\times 20\times 2=400 ft^3$

mass of water $=\rho \times volume$

mass $=62.4\times 400=24,960 lb$

This pool is in the form parallelepiped therefore average distance $=\frac{4+2}{2}=3$

Work $= 249600\times 3=74880 ft.lb$

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Read 2 more answers

Enter the equation of the line in slope-intercept form. Slope is -1/2, and (-9,4) is on the line. The equation of the line is y=

dezoksy [38]

Answer:

$y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)

1) Plug in the slope (m)

We're given that the slope is $\displaystyle-\frac{1}{2}$ . In $y=mx+b$ , replace m with $\displaystyle-\frac{1}{2}$ :

$y=\displaystyle-\frac{1}{2}x+b$

2) Determine the y-intercept (b)

$y=\displaystyle-\frac{1}{2}x+b$

We're given the point (-9,4). Plug this point into the equation as $(x,y)$ and solve for b:

$4=\displaystyle-\frac{1}{2}(-9)+b\\\\4=\displaystyle\frac{9}{2}+b$

Subtract $\displaystyle\frac{9}{2}$ from both sides to isolate b:

$4-\displaystyle\frac{9}{2}=\displaystyle\frac{9}{2}+b- \displaystyle\frac{9}{2}\\\\\displaystyle-\frac{1}{2} = b$

Therefore, the y-intercept is $\displaystyle-\frac{1}{2}$ . Plug this back into $y=\displaystyle-\frac{1}{2}x+b$ as b:

$y=\displaystyle-\frac{1}{2}x+(\displaystyle-\frac{1}{2})\\\\y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}$

I hope this helps!

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3 years ago