Question

A swimming pool has a rectangular base 10 ft long and 20 ft wide. The sides are 4 ft high, and the pool is half

Answer 1

Answer:74880 ft.lb

Step-by-step explanation:

Given

Dimension of pool

base=10 ft

width=20 ft

height=4 ft

Pool is half filled

volume of Pool$=10\times 20\times 2=400 ft^3$

mass of water$=\rho \times volume$

mass$=62.4\times 400=24,960 lb$

This pool is in the form parallelepiped therefore average distance$=\frac{4+2}{2}=3$

Work $= 249600\times 3=74880 ft.lb$