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sergiy2304 [10]
3 years ago
14

A swimming pool has a rectangular base 10 ft long and 20 ft wide. The sides are 4 ft high, and the pool is half

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:74880 ft.lb

Step-by-step explanation:

Given

Dimension of pool

base=10 ft

width=20 ft

height=4 ft

Pool is half filled

volume of Pool=10\times 20\times 2=400 ft^3

mass of water=\rho \times volume

mass=62.4\times 400=24,960 lb

This pool is in the form parallelepiped therefore average distance=\frac{4+2}{2}=3

Work = 249600\times 3=74880 ft.lb

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Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
What is 3/8 plus 1/12
Delvig [45]
first what you have to do you have to find the common denominator which is 24
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Yuki888 [10]
1 pound equals 16 ounces
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erastovalidia [21]
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