Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
<span>m(x) = –7x has an inverse which is a function.</span>
Answer:
(- 5, 1 )
Step-by-step explanation:
- 6x - 14y = 16 → (1)
- 2x + 7y = 17 → (2)
Multiplying (2) by - 3 and adding to (1) will eliminate the x- term
6x - 21y = - 51 → (3)
Add (1) and (3) term by term to eliminate x
0 - 35y = - 35
- 35y = - 35 ( divide both sides by - 35 )
y = 1
Substitute y = 1 into either of the 2 equations and solve for x
Substituting into (1)
- 6x - 14(1) = 16
- 6x - 14 = 16 ( add 14 to both sides )
- 6x = 30 ( divide both sides by - 6 )
x = - 5
solution is (- 5, 1 )
All you have to do is subtract 3/8 from 7 which would give you 9 and 1/3
Answer:
Step-by-step explanation:
We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)
We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.
We have to find the value of Sin(B). Sin of an angle is defined as:
The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:
