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Scrat [10]
3 years ago
14

How do you solve 2/7k - 3/8 = -19/8

Mathematics
1 answer:
Bad White [126]3 years ago
8 0
Alright, start with simplifying both sides
\frac{2}{7} k+ \frac{-3}{8} = \frac{-19}{8}
Than add \frac{3}{8} to both sides.
\frac{2}{7}k + \frac{-3}{8} + \frac{3}{8} =\frac{-19}{8} + \frac{3}{8}
which is \frac{2}{7} k=-2

After this, multiply each side by \frac{7}{2}
( \frac{7}{2})* \frac{2}{7} k= ( \frac{7}{2})*(-2)
 So, your final answer is K=-7


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If f(x) = x square - 4x + 6, find f(1) - f(-1)
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Answer:

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Step-by-step explanation:

Evaluate f(1) and f(- 1) by substituting x = 1 and x = - 1 into f(x)

Given

f(x) = x² - 4x + 6, then

f(1) = 1² - 4(1) + 6 = 1 - 4 + 6 = 3

f(- 1) = (- 1)² - 4(- 1) + 6 = 1 + 4 + 6 = 11

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First, convert 3 into a fraction with denominator 8.

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tanX is 12/5.

Given:

In a right triangle,

The length of the side <em>XY</em> = 13.

The length of the side <em>YZ</em> = 12.

The length of the side <em>XZ</em>= 5.

The objective is to find tan <em>X</em>.

In a right angled triangle the largest side is always hypotenuse.

Sinec tan <em>X</em> is required to solve, then, the side <em>YZ </em>is opposite side and the side <em>XZ</em> is adjacent side.

By the trigonometric ratios, the value of tan <em>X</em> can be calculated as,

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