All categories

2 years ago

If a third plane could be drawn which contains both lines a and b, then what must the lines be?

2 answers:

7 0

The line a and line b are parallel to each other since if you draw another line or a third plane and it contains both points both in line a and in line b it means that this third plane passes through to the both lines a and b. In order to achieve both lines a and b can be passed by the third plane, they should be parallel to each other.

Step2247 [10]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Please explain how you got your answer (:

melisa1 [442]

I used math

anyway
remember you can do anything to an equation as long as you do it to both sides

so

4n+2 and 1/2=2n+5
minus 2n both sides
4n-2n+2 and 1/2=2n-2n+5
2n+2 and 1/2=0+5
2n+2 and 1/2=5
minus 2 and 1/2 both sides
2n=2 and 1/2
divide both sides by 2
I mean times both sides by 1/2
n=1 and 1/4

answer is C

6 0

3 years ago

Consider the following set of equations:

alina1380 [7]

B. x+4=3x+6 ..........

3 0

3 years ago

The distance in feet that Karina swims in a race is represented by 6d - 6, where d is the distance for

vaieri [72.5K]

The answer would be a hope it helps

6 0

3 years ago

A semi circle is drawn on each side of the square as shown the square has sides length of 2 pi what is the area of the resulting

Marina86 [1]

Step-by-step explanation:

First you find out the area of the square.

Then you find the area of the circle.

After this you add the Two area together.

7 0

3 years ago

find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS

charle [14.2K]

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

8 0

3 years ago