This is an approximately bell-shaped distribution. The highest bar is in the center, with height = 12. Just to its left and right are bars of heights 6 and 5. At the extremes are bars of heights 2 and 1.
If the highest bar was on the left, it would be skewed left (and if it was on the right, skewed right). A uniform distribution would more or less have the same height level over all the bars.
Would be the last answer because (n-3)times (n-3) is n^2-6n+9
So whats the rest of this question? its uncompleted.
Answer:
Absolute error = 39
Percent Error = 6.10%
Step-by-step explanation:
Actual value = 639 pounds
Observed Value = 600 pounds
The formula to find absolute error is:
Absolute Error = Actual value - Observed Value
= 639 - 600
= 39
The formula to find Percent error is:
Percent Error = (Actual value - Observed Value / Actual value)*100
= (639 - 600/639)*100
= 6.10%
Answer:
-83
Step-by-step explanation:
so plug in 10 in 8x. So it is 10*-8 -3.
-80-3=-83
