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3 years ago

11

Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time

s did Jenny save $250 for the month?
A) 3
B) 4
C) 5

2 answers:

kari74 [83]3 years ago

7 0

5 months for it 5 times 250= 1250

Sergio039 [100]3 years ago

6 0

Solution:

we are given that

Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month.

we have been asked to find that

During the 12 month period, how many times did Jenny save $250 for the month?

Let Jenny saved x times $250, it Jenny saved (12-x) times $350, then we can write

$250x+(12-x)350=3800\\ \\ \text{Solve for x}\\ \\ 250x+12*350-350x=3800\\ \\ 100x=4200-3800\\ \\ 100x=400\\ \\ x=4\\$

Jenny saved 4 times $250

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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

A granola bite contains 27 calories. Most of the calories come from c grams of carbohydrates. The rest come from other ingredien

joja [24]

Answer:

a. 5 represents the number of calories that come from other ingredients.

b. Neither 8 nor 3 satisfy the given equation, so neither 8 nor 3 can be the solution to the equation.

c. <em>c = 5.5</em>

Step-by-step explanation:

We are given the equation:

$4c + 5 = 27$

Where $c$ represents the grams of carbohydrates

27 is the total number of calories that are received by the granola bite.

4 is the number of calories from 1 gram of carbohydrates and

5 is the number of calories that are received from other ingredients.

Answer of Part a:

5 is the number of calories that are received from other ingredients.

Part b:

Let us take left hand side (LHS) and put values of c = 8 and 3 one by one.

So, LHS becomes:

4 \times 8 + 5 = 37 $\neq RHS\ i.e.\ 27$

4 \times 3 + 5 = 17 $\neq RHS\ i.e.\ 27$

So, Priya is correct that neither 8 or 3 could be solution.

Part c:

$4c + 5 = 27\\\Rightarrow 4c = 22\\\Rightarrow \bold{c = 5.5}$

So, solution to the equation is: <em>c = 5.5</em>

8 0

3 years ago