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JulijaS [17]
3 years ago
14

3 connecting lines are shown. Line A B is horizontal. Line A C is about half the length of A B. Line B C is about one-third of t

he length of A B.
Which inequality can be used to explain why these three segments cannot be used to construct a triangle?

AC + AB > CB
AC + CB < AB
AC + CB > AB
AC + AB < CB
Mathematics
1 answer:
lidiya [134]3 years ago
5 0

Answer:

AC + CB < AB

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The graph of f(x) = x3 + x2 – 9x – 9 is shown.
lys-0071 [83]

Answer:

the third option, x = –3, –1, 3

Step-by-step explanation:

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2 years ago
Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 &lt; t &lt; π
pogonyaev
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

y=\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
x=\cos2t\implies\dfrac{\mathrm dx}{\mathrm dt}=-2\sin2t=-4\sin t\cos t
\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-\sin t}{-4\sin t\cos t}=\dfrac14\sec t

Let z=\dfrac{\mathrm dy}{\mathrm dx}. Then

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac{\frac{\mathrm dz}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}
\implies\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac{\mathrm d}{\mathrm dt}\left[\frac14\sec t\right]}{-4\sin t\cos t}=\dfrac{\frac14\sec t\tan t}{-4\sin t\cos t}=-\dfrac1{16}\sec^3t
4 0
4 years ago
A 77 m tall building casts a 36 m shadow.
lidiya [134]

Answer:

its a 65 degree angle

Step-by-step explanation:

8 0
3 years ago
2. At a rate of 50 mph, a car travels a distance
Sergio039 [100]

Answer: 480 miles

Step-by-step explanation:

first you divide 600 by 50 and thats the amount of hours.

600 / 50 = 12

then multiply 40 x 12 and you got your answer. :)

40 x 12 = 480 therefore your answer is 480

5 0
2 years ago
Is this the right answer?,please help before I turn it in
astraxan [27]
Yes it’s the right answer, I just did it myself and I got -4
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