Answer:
A=a+b
2h
Step-by-step explanation:
Answer:
-3
The problem:
The sum of four consecutive integers is - 18. What is the greatest of these
integers?
Step-by-step explanation:
If n is the first integer, then n+1 is the second integer, n+2 is the third integer, and n+3 is the fourth integer in consecutive order.
For example if n=8, we are saying n+1=9,n+2=10, and n+3=11, which I think you can see that 8,9,10,11 are consecutive.
So the sum is -18 which means:
n+(n+1)+(n+2)+(n+3)=-18
4n+6=-18
Subtract 6 on both sides:
4n=-18-6
Simplify:
4n=-24
Divide both sides by 4:
n=-6
If n=-6,
then:
n+1=-6+1=-5
n+2=-6+2=-4
n+3=-6+3=-3.
So the 4 consecutive integers whose sum is -18 is: -6,-5,-4, and -3.
The greatest of these integers is -3.
4 Pencils cost 0.50$.
So 8 Pencils would cold 1.00$
1/2 of 0.50$ is 0.25$
Therefore, 10 Pencils would cost 1.25$ !
Answer:
A vacuum
Step-by-step explanation:
