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Ratling [72]
3 years ago
6

What is the slope of the line shown below?

Mathematics
1 answer:
fiasKO [112]3 years ago
3 0

Answer: The slope of the line can be determined from the gradient equation, rise (y axis)/ run (x-axis)

Hence let (-1, 8) be A and (2, -4) be B. The slope from A to B is (-4-8)/(2-(-1))= (-12)/3= -4

Hence the gradient/ slope of the line is -4.

Step-by-step explanation:

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Answer:

B.) The graph of m(x) is wider.

     Both graphs open upward.

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     The vertex of m(x) is (0, 4); the vertex of n(x) is (0, 0).

Step-by-step explanation:

When the coefficient before x² is greater than 1, the curve of the graph is narrower. When the coefficient is less than 1, the curve of the graph is wider.

When the coefficient in front of x² is positive, the graph opens upwards. When the coefficient is negative, the graph opens downwards.

The axis of symmetry is the "x" value which divides the curve into two equal sections. Their axis of symmetry are both x = 0 because their vertexes (the lowest point of the curve) are both at x = 0.

The vertex can be found by plugging x = 0 into both of the equations and then solving. The resulting value is the "y" position of the vertex.

m(0) = 0.7(0)² + 4                        n(0) = (0)²

m(0) = 0 + 4                                 n(0) = 0

m(0) = 4

Therefore, the vertexes are m(x) =  (0,4) and n(x) = (0,0).

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