Answer:
the correct answer is shown below
Step-by-step explanation:
hope this helps
Observe attached picture.
On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft
When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.
We can apply trigonometry rules to find height of flagpole.
From small triangle containing sign we can find tangens function:

Similarly we can do for large triangle containing flagpole:

We see that these two equations have same left sides. This means that their right sides must also be same:

We can solve for A:

Height of flagpole is 48 feet.
Answer:
Area = 21/2 = 10.5 area units
Step-by-step explanation:
Two of the points are on the same line (the y-axis) as they both have x-coordinates of 0. This can thus be the base of your triangle.
Two more are on the same line (y= -9) as they both have the same y-coordinate of -9. This can be the height of your triangle.
So you have a base which is between -2 and -9 (7 units) and a height which is between 0 and 3 (3 units) so now just use the equation for area of a triangle
Sine is positive while cotangent is negative. So this must mean cosine is negative since cos/sin = cot. In other words, cotangent is the ratio of cosine over sine.
Because cosine is negative and sine is positive, this places theta in quadrant 2
This is where x < 0 and y > 0. Recall that on the unit circle, x = cos(theta) and y = sin(theta).
The answer is choice B) quadrant II
<span>for part (a) find the sum of the first n terms of the arithmetic series. for part (b) find n for the given sum Sn.
45. 3+8+13+18+23+...
a. n=20
b. Sn=366
46. 50+42+34+26+18+...
a. n=40
b. Sn=182
47. -10+(-5)+0+5+10+...
a. n=19
b. Sn=375
48. 34+31+28+25+22+...
a. n=32
b. Sn=-12
49. 2+9+16+23+30+...
a. n=68
b. Sn=1661
50. 2+16+30+44+58+...
a. n=24
b. Sn=2178
</span>