The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
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Answer:
t = 9.57
Step-by-step explanation:
We can use trig functions to solve for the t
Recall the 3 main trig ratios
Sin = opposite / hypotenuse
Cos = adjacent / hypotenuse
Tan = opposite / adjacent.
( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )
We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"
When dealing with the opposite and adjacent we use trig ratio tan.
Tan = opp / adj
angle measure = 62 , opposite side length = 18 and adjacent = t
Tan(62) = 18/t
we now solve for t
Tan(62) = 18/t
multiply both sides by t
Tan(62)t = 18
divide both sides by tan(62)
t = 18/tan(62)
t = 9.57
And we are done!
Answer: 4.500
Step-by-step explanation:
4x - 18 = 2 • (2x - 9)
2 = 0
2x-9 = 0
2x = 9
x = 9/2 = 4.500
Answer:
yeah
Step-by-step explanation:
wrong subject dude
things go wrong sometimes
you lost 46 points
