Answer:
134.04
Step-by-step explanation:
<span>Number part = <span>3.3 </span></span>and
<span>Exponent part = -7</span>
<span>3.3*<span>10<span>−7</span></span></span>

<h3><u>Analysis </u><u>of </u><u>graph </u><u>:</u><u>-</u></h3>
We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- For the first 5 minute ( O to A) , The distance is continously increasing 2m / per minute .
- For the 5 minute that is from 5 minute to 13 minute ( A to B) both marellize and her dog wally moving with the constant speed .
- For next 3 minutes that is from 10 minutes to 13 minutes ( B to C) , The distance is continously decreasing with time .
- For next 3 minutes that is from 13 to 16 minutes ( C to D) , Again they moved with constant speed .
- For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
- Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
1) Between O and A
- The marellize and wally when moving between O to A , The distance is constantly increasing with time.
- The graph is Straight line
2) Between A and B
- The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
- The graph is constant or steady
3) Between B to C
- The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
- The graph is straight line but it follows decreasing function .
4) For covering the First 6 km ,
<u>According </u><u>to </u><u>the </u><u>graph</u><u>, </u>
- For covering first 6 km, They took 3 minutes.
5) No, Marellize and wally walk does not from where they have started.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- It is end at 5 m instead of 0m .
Answer:
(2, -5)
Step-by-step explanation:
Convert to vertex form:
3x^2 - 12x + 7
= 3(x^2 - 4x) + 7
Completing the square:
= 3[ (x - 2)^2 - 4)] + 7
= 3(x - 2)^2 - 12 + 7
= 3(x - 2)^2 - 5.
Comparing with the general form
a(x - b)^2 + c we see that the vertex is (b, c) = (2, -5).