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Lena [83]
3 years ago
9

What is the greatest common factor of 84 and 210​

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0

Answer:

42 is your answer!

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−6x+14<−28 OR 9x+15≤−12
Serhud [2]

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is 70 divided by 7 1/2
Tresset [83]

Answer:

9.333333 (repeating decimal)

5 0
2 years ago
Read 2 more answers
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h
Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

P(t) = P(0)(1+r)^{t}

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that r = 0.047

$172000 in 2004

This means that P(0) = 172000

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

P(t) = P(0)(1+r)^{t}

249000 = 172000(1.047)^{t}

(1.047)^{t} = \frac{249000}{172000}

\log{(1.047)^{t}} = \log{\frac{249000}{172000}}

t\log(1.047) = \log{\frac{249000}{172000}}

t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}

t = 8.05

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0
3 years ago
42 is 8% of what number
Setler [38]
8%=0.08
42÷0.08=525
So your answer is 525
7 0
3 years ago
Read 2 more answers
Which logarithmic equation is equivalent to this exponential equation? <br><br> 12=5^x
Brut [27]

Given:

The equation is:

12=5^x

To find:

The logarithmic equation that is equivalent to the given exponential equation.

Solution:

According to the property of logarithm:

a=b^x\Leftrightarrow \log_b a=x

We have,

12=5^x

Here, a=12,b=5. By using the above property of logarithm, we get

\log_{5}12=x

x=\log_{5}12

Therefore, the correct option is C.

5 0
3 years ago
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