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Andrej [43]
3 years ago
11

Mr. Atkinson manages playgrounds for the 8 elementary schools in the Franklin School District. This year, he wants to put new sa

ndboxes at each of the schools. He estimates that he will need 3 tons of sand for this project. How many 50-pound bags of sand should he order for each school?
Mathematics
2 answers:
astra-53 [7]3 years ago
8 0

Answer: 5 bags of sand

Step-by-step explanation:

Given

There are 8 elementary schools

3 Tons of sand is needed

It is contained in a 50- Pound bag

1 ton is equivalent to 2000 Pound

No of 50- Pound bag required is

\Rightarrow n=\dfrac{2000}{50}\\\\\Rightarrow n=40

These 40 bags will be required in 8 schools. So, each school requires

\Rightarrow \dfrac{40}{8}=5\ \text{bag}

Paraphin [41]3 years ago
4 0

Answer:

The number of bags required for each school is 16.53

Step-by-step explanation:

Number of schools = 8

Total sand required = 3 tons

mass of each bag = 50 pounds

Sand required for each school = 3 ton/ 8 = 3000 / 8 kg = 375 kg

1 pound = 0.454 kg

1 kg = 2.205 pounds

So, 375 kg = 826.7 pounds

So, the number of bags required for each school =  826.7/50 = 16.53 bags

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What number should be added to both sides of the equation to complete the square x^2+3x=6
Allisa [31]
Take half of the coefficient of x:  It is 3, and half that is 3/2.


Then   <span>x^2+3x=6  becomes:

</span><span>           x^2+3x + (3/2)^2 =6 + (3/2)^2, and

             (x+3/2)^2 = 6 + 9/4

You were not asked to solve the equation, but why not do it for the practice?

</span>Solve (x+3/2)^2 = 6 + 9/4 for x.  There will be 2 values.
8 0
4 years ago
Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 5(cos(25) + isin(25)) z2 = 2(cos(80) +
zmey [24]

solution:

Z1 = 5(cos25˚+isin25˚)

Z2  = 2(cos80˚+isin80˚)

Z1.Z2  = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)

Z1.Z2  = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }

Z1.Z2  =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}

(i^2 = -1)

Cos(A+B) = cosAcosB – sinAsinB

Sin(A+B) = sinAcosB + cosAsinB

Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)

 Z1.Z2     = 10(cos105˚+ isin105˚)


5 0
4 years ago
Which of the following sets include all rational numbers?
kicyunya [14]

It's the Second one and the third one

Step-by-step explanation:

Pie is irrational so you can easily cross it off and it leads to to the second one and the third one

4 0
3 years ago
Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha
GalinKa [24]

Answer:

\theta_1 \ n\ \theta_2 = 120, 240

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

Nonagon = 9\ sides

Hexagon = 6\ sides

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

\theta = \frac{360}{9} =40

List the multiples of 40

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

<u>Hexagon</u>

\theta = \frac{360}{6} =60

List the multiples of 60

\theta_2 = 60, 120, 180, 240, 300

List out the common angles

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

\theta_2 = 60, 120, 180, 240, 300

\theta_1 \ n\ \theta_2 = 120, 240

This means that, only a rotation of 120, 240 will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

7 0
3 years ago
What is 30/40 converted into a percent
juin [17]

75%

30/40 means its 75% out of 100%

75$ representing the 30 and the 100$ representing the 40

7 0
3 years ago
Read 2 more answers
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