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Phoenix [80]
3 years ago
7

4a^2+2a+4a^2-5 Simplify the expression

Mathematics
2 answers:
frozen [14]3 years ago
5 0
Add <span><span>4<span>a2</span></span><span>4⁢<span>a2</span></span></span> and <span><span>4<span>a2</span></span><span>4⁢<span>a2</span></span></span> to get <span><span>8<span>a2</span></span><span>8⁢<span>a2</span></span></span> .<span><span><span><span>8<span>a2</span></span>+<span>2a</span></span><span>−5</span></span><span><span><span>8⁢<span>a2</span></span>+<span>2⁢a</span></span><span>-<span>5</span></span></span></span>
raketka [301]3 years ago
4 0
it would be 8a^2+2a-5 but if u need value of a you can apply quadratic formula
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Bradford starting his first newspaper route. He will deliver 17 newspapers. A newspaper subscription cost each customer six doll
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10m/
AlladinOne [14]

Answer:

Answer is D 312m^2

As  D= 8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

This makes triangle base of 6m

triangle side =8m

Rectangle side = 8m

and rectangle length = 11m

Step-by-step explanation:

First finding

A= 6 x 11 = 66m^2 (rectangle area) or 10 x 9 = 90sq^2

A = 1/2 x 6 x 11 = 33  (1/2bh) triangle

33+ 33 + 66 +66 + 66 = 264  or 33+ 33+ 90+90+90 =336

As 336 was not in the answer we do not know what 10m/9m represents, we then see this triangle prism is not a normal shape and its length is same as its height

a) is not in usual proportions.

We try again reversing which makes triangle sides 10m+ base 9m

= 1/2 x 10 x 10 = 50m^2 = triangle face area

we cannot continue the reverse as the triangle sides do not match the rectangle height. We therefore have to use the first answer C 264m^2

As 10m, 9m <do not match >6m 11m 8m

However if the given sizes 10m, 9m = bases of two different rectangles we would calculate 2 faces and add them each to one unknown face being one of the other face sizes we found to make 3.

10 x 8 = 80

9 x 8 = 72

To make one of these SA totals for rectangles alone

=80+80+72=232   or  72+72+80 =224

Then add to the 33 m^2 triangles

= 232+ 33+ 33 =297m^2

= 224+33+33 =310m^2

We can now determine that these measurements represent irregular values and are not answers within multiple choice, however d)  we can state the triangle is regular prism where triangle sides are regular too creating isosceles triangle 6,8,8,

8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

As we have ruled out rectangle with side 8m x 11m + A (33m^2) of triangle would equal 310m^2 (88+88+88+33+33) =330m

And ruled out rectangle with side 8m x 6m= 48m^2 (48+48+48+33+33 =210sqm)

So therefore if triangles were to equal 1/2 x 6 x 8 = 24

24 x 3= 72sqm

add the rectangle amounts above

= 72 + 88+ 88+ 88 =336^2

try another way and we find D. here below.

answer D= 72+ 80+80+80 = 312m^2 this can makes a correct answer D.

As last rule out is;

72 + 72 +72  (+triangle of 72) =288^2 would be irregular as this is equal to (9 x 8) x 3 and then the 11m is not used. It is also not a listed answer. Therefore;  D=312m^2 is correct.

A triangular prism has three rectangular sides and two triangular faces. To find the area of the rectangular sides, use the formula A = lw, where A = area, l = length, and h = height. To find the area of the triangular faces, use the formula A = 1/2bh, where A = area, b = base, and h = height.

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What are two ways friction can be increased
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By making the surface rougher and to increase the force pushing the surfaces together.
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Which property is shown in the following statement? (46 + 17) + 3 = 46 + (17 + 3) identity property of addition associative prop
maksim [4K]

Answer: the associative property of addition

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1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β
slava [35]

Step-by-step explanation:

1.

\tan \beta  =  \frac{1}{ \cot \beta }  =  -  \frac{3}{2 \sqrt{10} }  =  -  \frac{3 \sqrt{10} }{20}

\csc \beta  \tan \beta  =  \frac{1}{ \cos \beta  }  =  \sec \beta

Therefore,

\sec \beta  = ( \frac{7}{3} )( -  \frac{3 \sqrt{10} }{20} ) =  -  \frac{7 \sqrt{10} }{20}

2.

\csc y =  \frac{1}{ \sin y}  =  -  \frac{ \sqrt{6} }{2}

=  >  \sin y =  -  \frac{ \sqrt{6} }{3}

Use the identity

\cos y =   \sqrt{1 -  \sin ^{2} y}    \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \\ =  \sqrt{1 -  {( -  \frac{ \sqrt{6} }{3}) }^{2} }  =  -  \frac{ \sqrt{3} }{3}

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

\tan \beta  =  \frac{ \sin y}{ \cos y} =( -  \frac{ \sqrt{6} }{3} )( -  \frac{3}{ \sqrt{3} } ) =  \sqrt{2}

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

\sin x =   \sqrt{1 -  \cos ^{2} x} =  \sqrt{ \frac{11}{6} }

Solving for tan x:

\tan x =  \frac{ \sin x}{ \cos x}  =  (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) =  \frac{ \sqrt{66} }{5}

5 0
3 years ago
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