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3 years ago

Solve the inequality.

Mathematics

2 answers:

Marianna [84]3 years ago

5 0

Hello the Answer:x>15

nordsb [41]3 years ago

4 0

I think it is x=20 because 20/5 = 4 and 4 is greater then 3

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Helpppppppp here plz

miv72 [106K]

Answer:

x + x+12 + 3(x+12) = 123

x = 15

Step-by-step explanation:

Jamil : x

Kiera : x+12

Luther : 3 ( x+12)

x + x+12 + 3(x+12) = 123

Distribute

x + x+12 + 3x+36 = 123

Combine like terms

5x+ 48 = 123

Subtract 48 from each side

5x+48-48 = 123-48

5x =75

Divide by 5

5x/5 = 75/5

x = 15

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME WILL GIVE BRAINLIEST FOR RIGHT ANSWER

Sladkaya [172]

Answer:

Step-by-step explanation:

I dont really know how to find out the variables but what i assume to do is this:

Find the square root of n and add it to m. The sum of both you divide by p. then when you figure that out, you distribute the x value into the parenthesis. This might be obvious but i looked at this question for 10 minutes and couldnt find the value sorry :(

6 0

2 years ago

Read 2 more answers

I'm can't seem to find a common base. I know the answer's x=4 but I thought it was x=0.

EleoNora [17]

64^x = 256 * 16^x

2^6x = 2^8 * 2^4x

2^6x = 2^(4x+8)

6x = 4x +8

2x = 8

x = 4

7 0

3 years ago

Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.

Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that $n = 20, \pi = \frac{8}{20} = 0.4$ .

95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147$

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

3 0

4 years ago

Given that ABCD is a rhombus, what is the value of x?

Maslowich

Answer:

Step-by-step explanation:

We know that diagonals bisect angles of a rhombus, meaning that they split the angles of two equal parts, that opposite angles are equal, and that the angles of a quadrilateral, such as a rhombus, add up to 360 degrees.

Looking at the drawing I uploaded, and taking into account that diagonals bisect angles of a rhombus, we can say that angle x = y and z = 5x-18

Next, given that opposite angles are equal, we can say that angle B = angle D and angle A = angle C. Therefore,

A+B+C+D= 360 (as the angles of a quadrilateral add up to 360)

A + B + A + B = 360 (plugging in A for C and B for D)

2 ( A + B) = 360

A + B = 180

x + y + z + 5x - 18 = 180 (plugging x+y in for A, and z+5x-18 in for B, as x and y make up A and z and 5x-18 make up B)

x+x+5x-18+5x-18 = 180 (because x=y and z=5x-18)

2(x+5x-18) = 180

divide both sides by 2

x+5x-18=90

6x-18=90

add 18 to both sides

6x=108

divide both sides by 6

x = 18

4 0

3 years ago