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2 years ago

True or false the sum of two negative numbers is always negative explain why or why not this is true or false

Mathematics

2 answers:

Igoryamba2 years ago

8 0

Answer:

true!

Step-by-step explanation:

if you add negative numbers together, it will have to be negative because you are not adding positive numbers. same thing with positive numbers, if you add two positive numbers together, the sum will be a bigger positive number!

erma4kov [3.2K]2 years ago

3 0

Answer:

true

Step-by-step explanation:

Let's say you have -7 dollars in your bank account, and then you go and spend 5 more, which is -5, now you have -12 bucks in your account

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B3BB

skad [1K]

Answer:

C is correct

Step-by-step explanation:

Firstly, we have to solve for x in the solution set of the inequality

We have this as follows;

x + 2 ≥ 6

x ≥ 6-2

x ≥ 4

To graph this, we consider the middle sign which is greater than or equal to

So, the inequality sign has to face the right side

secondly, it has to be shaded on the point 4 due to the fact that it has the ‘equal to’ beneath the single inequality symbol

so, the correct answer here is option C

6 0

2 years ago

Solve the system using substitution method <br> 3x+y=6<br> 2x-4y=10

Andreyy89

$\left\{\begin{array}{ccc}3x+y=6&|-3x\\2x-4y=10\end{array}\right\\\\\left\{\begin{array}{ccc}y=6-3x\\2x-4y=10\end{array}\right\\\\substitute\ y=6-3x\ to\ the\ second\ equation\\\\2x-4(6-3x)=10\\\\2x-4\cdot6-4\cdot(-3x)=10\\\\2x-24+12x=10\\\\14x-24=10\ \ \ |+24\\\\14x=34\ \ \ \ |:14\\\\x=\dfrac{34}{14}\to x=\dfrac{17}{7}\\\\substitute\ the\ value\ of\ x\ to\ first\ equation\\\\y=6-3\cdot\dfrac{17}{7}=6-\dfrac{51}{7}=\dfrac{42}{7}-\dfrac{51}{7}=-\dfrac{9}{7}$

$\boxed{\left\{\begin{array}{ccc}x=\dfrac{17}{7}\\\\y=-\dfrac{9}{7}\end{array}\right}$

5 0

2 years ago

Read 2 more answers

How do I solve b/4 = 9

frutty [35]

<span>Simplifying b4 = 9 Solving b4 = 9 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Simplifying b4 = 9 Reorder the terms: -9 + b4 = 9 + -9 Combine like terms: 9 + -9 = 0 -9 + b4 = 0 Factor a difference between two squares. (3 + b2)(-3 + b2) = 0</span>

8 0

2 years ago

Read 2 more answers

Hose 1 in June took 45 mins to fill a pool of height of 20 inches and length 110 inches. Hose 2 in July took 15 mins to fill the

worty [1.4K]

Answer:

there isnt enough evidence to colclude an answer

Step-by-step explanation:

6 0

2 years ago

Prove the divisibility of the following numbers:

Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

$75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}$

(B)

$72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}$

In this case, it is easier to also factor the divisor to primes:

$72^{63}=2^{189}\cdot 3^{126}$

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

$2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}$

6 0

2 years ago