We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.
F '(x) = -4x^3 - 27x^2 - 48x - 16 You must set this = to 0 and solve for the
roots (which we call "critical values).
F "(x) = -12x^2 - 54x - 48
Now suppose you've found the 3 critical values. We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).
Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:
F "(x) = -12x^2 - 54x - 48 becomes F "(4) = -12(4)^2 - 54(4)
= -192 - 216
Because F "(4) is negative, the graph of the given
function opens down at x=4, and so we have a
relative max there. (Remember that "4" is only
an example, and that you must find all three
critical values and then test each one in F "(x).
Table C represents a function
This is because each x value has only one y value. For the other tables, the x values of 4, 9, and 8 have 2 different y values.
$10.50 gets taken off the original price. I divided $42 by 4 because 25 is 1/4th of 100. This got me $10.50. The original price ($42) minus $10.50 equals $31.50. So the item sells for $31.50!!!!
A is the answer your looking for
Answer:
60.6%
0.0003%
Step-by-step explanation:
Because they are independent events, the final probability will be the multiplication of each event, that is, 0.92 multiplied 6 times, in other words:
0.92 ^ 6 = 0.606
that is to say that the probability that the 6 men survive is 60.6%
Now, to calculate that at least one survives, it means that 5 died, the probability that one dies is 1 - 0.92 = 0.08, and how they are 5 would be:
0.08 ^ 5 = 0.0000032768
Then multiplied by 0.92, which is that one survives, we are left with:
0.0000032768 * 0.92 = 0.00000301465
Which means that the probability of one surviving is 0.0003%, it is a very low probability because the probability of surviving is really high.
