1.
D
2.
D
3.
A and D
4.
Didn't Understand
retype in comment and send
Answer:
a = 4
Step-by-step explanation:
![\sin(theta) = \frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Csin%28theta%29%20%20%3D%20%20%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%20)
![\cos(theta) = \frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Ccos%28theta%29%20%20%3D%20%20%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20)
![\tan(theta) = \frac{opposite}{adjacent}](https://tex.z-dn.net/?f=%20%5Ctan%28theta%29%20%20%3D%20%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20)
hypotenuse = a
opposite = 2√3
adjacent = b
theta = 60°
the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a
![\sin(60) = \frac{2 \sqrt{3} }{a}](https://tex.z-dn.net/?f=%20%5Csin%2860%29%20%20%3D%20%20%5Cfrac%7B2%20%5Csqrt%7B3%7D%20%7D%7Ba%7D%20)
![\frac{2 \sqrt{3} }{ \sin(60) } = a](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%5Csqrt%7B3%7D%20%7D%7B%20%5Csin%2860%29%20%7D%20%20%3D%20a)
![4 = a](https://tex.z-dn.net/?f=4%20%3D%20a)
![a = 4](https://tex.z-dn.net/?f=a%20%3D%204)
Answer:
60%
Step-by-step explanation:
A 40% discount means that 40% will be off, meaning you won't have to pay 40% of the original price. Therefore, you only pay 60% of the original price (100% - 40% = 60%).
Answer:
The IQR is given by:
![IQR = Q_3 -Q_1 = 28-18= 10](https://tex.z-dn.net/?f=%20IQR%20%3D%20Q_3%20-Q_1%20%3D%2028-18%3D%2010)
If we want to find any possible outliers we can use the following formulas for the limits:
![Lower= Q_1 - 1.5 IQR](https://tex.z-dn.net/?f=Lower%3D%20Q_1%20-%201.5%20IQR)
![Upper= Q_3 + 1.5 IQR](https://tex.z-dn.net/?f=Upper%3D%20Q_3%20%2B%201.5%20IQR)
And if we find the lower limt we got:
![Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3](https://tex.z-dn.net/?f=Lower%3D%20Q_1%20-%201.5%20IQR%3D%2018-1.5%2A10%20%3D%203)
![Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43](https://tex.z-dn.net/?f=Upper%3D%20Q_3%20%2B%201.5%20IQR%3D%2028%2B1.5%2A10%3D%2043)
So then the left boundary for this case would be 3 days
Step-by-step explanation:
For this case we have the following 5 number summary from the data of 144 values:
Minimum: 9 days
Q1: 18 days
Median: 21 days
Q3: 28 days
Maximum: 56 days
The IQR is given by:
![IQR = Q_3 -Q_1 = 28-18= 10](https://tex.z-dn.net/?f=%20IQR%20%3D%20Q_3%20-Q_1%20%3D%2028-18%3D%2010)
If we want to find any possible outliers we can use the following formulas for the limits:
![Lower= Q_1 - 1.5 IQR](https://tex.z-dn.net/?f=Lower%3D%20Q_1%20-%201.5%20IQR)
![Upper= Q_3 + 1.5 IQR](https://tex.z-dn.net/?f=Upper%3D%20Q_3%20%2B%201.5%20IQR)
And if we find the lower limt we got:
![Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3](https://tex.z-dn.net/?f=Lower%3D%20Q_1%20-%201.5%20IQR%3D%2018-1.5%2A10%20%3D%203)
![Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43](https://tex.z-dn.net/?f=Upper%3D%20Q_3%20%2B%201.5%20IQR%3D%2028%2B1.5%2A10%3D%2043)
So then the left boundary for this case would be 3 days