0.04444444444All you have to do is divide 2/3 by 3/5.
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
-2 and -7
Step-by-step explanation:
This problem is about using the Factoring X.
Two numbers will multiply to the number placed at the top. These same two numbers will add to the value placed on the bottom.
Let's look at the factors of 14.
1 • 14 = 14
2 • 7 = 14
Now let's look at their sums.
1 + 14 = 15
2 + 7 = 9
We can see that 2 and 7 multiply to 14 and add to 9.
However, we need them to add to -9.
Note that two negative numbers multiplied will become positive.
-2 • - 7 = 14
Now let's look at their sum.
-2 + (-7)
Simplify the negative.
-2 - 7 = -9
We can see that -2 and -7 multiply to 14 and add to -9.
Hope this helps!
