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3 years ago

Need help please I’m begging yeah.

Mathematics

1 answer:

Simora [160]3 years ago

4 0

Answer: The answer is B.

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I will get my points but answer it correctly and no LINKS!!! (factotise by using a suitable identity X5-X)

9966 [12]

x(x-1)(x+1)(x²+1)=0

Hope it helps you

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3 years ago

Solve for j show work<br> 8j-5+j=67

andrew11 [14]

Answer:

Step-by-step explanation:

8j-5+j=67

8J+j

9J-5=67

+5 +5

9J=72

/9 /9

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3 years ago

The product of two inductive odd integers

vaieri [72.5K]

Let m and n be any integers so that 2m and 2k are two even numbers.

The product is 2m(2k) = 2(2mk), which is even.

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3 years ago

Solve for x and y. y=6x+4 y=4x-2

Marizza181 [45]

$\left\{\begin{array}{ccc}y=6x+4&(1^o)\\y=4x-2&(2^o)\end{array}\right\\\\\\subtitute\ (1^o)\ to\ (2^o):\\\\6x+4=4x-2\ \ \ \ |subtract\ 4\ from\ both\ sides\\6x=4x-6\ \ \ \ |subtract\ 4x\ from\ both\ sides\\2x=-6\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-3}\\\\subtitute\ value\ of\ "x"\ to\ the\ (1^o):\\y=6(-3)+4=-18+4\to \boxed{y=-14}$

$Answer:\boxed{ \left \{ {{x=-3} \atop {y=-14}} \right}$

4 0

3 years ago

Read 2 more answers

What's the answer to both when simplifying the two radical expression?

OlgaM077 [116]

$( \sqrt{x} +2 \sqrt{5})*( \sqrt{x} -2 \sqrt{5}) = \\ \\ ( \sqrt{x})^2- (\sqrt{x} *2 \sqrt{5})+(2 \sqrt{5}* \sqrt{x}) -(2 \sqrt{5})^2 = \\ \\ x- 2\sqrt{5} \sqrt{x}+2 \sqrt{5} \sqrt{x} -(4*5)= \\ \\ x -(4*5)= \boxed{x-20} \\ \\$

$( \sqrt{x}+ \sqrt{5}) ^2= \\ \\ ( \sqrt{x})^2+2* \sqrt{x}* \sqrt{5} + (\sqrt{5}) ^2= \\ \\ \boxed{ x +2 \sqrt{5x}+5}$

7 0

3 years ago