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zavuch27 [327]
3 years ago
7

Need help please I’m begging yeah.

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer: The answer is B.

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x(x-1)(x+1)(x²+1)=0

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Answer:

8

Step-by-step explanation:

8j-5+j=67

8J+j

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The product of two inductive odd integers
vaieri [72.5K]

Let m and n be any integers so that 2m and 2k are two even numbers.

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Solve for x and y. y=6x+4 y=4x-2
Marizza181 [45]
\left\{\begin{array}{ccc}y=6x+4&(1^o)\\y=4x-2&(2^o)\end{array}\right\\\\\\subtitute\ (1^o)\ to\ (2^o):\\\\6x+4=4x-2\ \ \ \ |subtract\ 4\ from\ both\ sides\\6x=4x-6\ \ \ \ |subtract\ 4x\ from\ both\ sides\\2x=-6\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-3}\\\\subtitute\ value\ of\ "x"\ to\ the\ (1^o):\\y=6(-3)+4=-18+4\to \boxed{y=-14}

Answer:\boxed{ \left \{ {{x=-3} \atop {y=-14}} \right}
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What's the answer to both when simplifying the two radical expression?
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( \sqrt{x}+ \sqrt{5}) ^2=   \\  \\   ( \sqrt{x})^2+2* \sqrt{x}* \sqrt{5} + (\sqrt{5}) ^2=   \\  \\   \boxed{  x +2 \sqrt{5x}+5}
7 0
3 years ago
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