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Readme [11.4K]
3 years ago
15

Triangle abc is congruent to triangle a” b” c” which sequence of transformations could have been used to form triangle abc to pr

oduce triangle a”b”c”
Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

where are the transformations

Step-by-step explanation:

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Is lmn congruent to opq if so name the postulate
insens350 [35]

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

                   Statements                      Reasons

1). LM ≅ OP                                   1). Given

2). MN ≅ PQ                                 2). Given

3). ∠P ≅  ∠M                                3). Given

4). ΔLNM ≅ ΔOQP                      4). By the SAS postulate of congruence.

                                                         [Side - Angle - Side]                          

Therefore, Option (A) will be the answer.

5 0
3 years ago
A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s
777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que <u><em>los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.</em></u>

7 0
2 years ago
Two numbers have a product of -36<br> They have a sum of -5<br> What are the two numbers?
neonofarm [45]

Answer:

-9,4

Step-by-step explanation:

4 0
2 years ago
Blank a function is the same as moving a function
earnstyle [38]

Answer:

Shifting/Translating the function

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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