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3 years ago

A ruler costs pence.

Mathematics

1 answer:

Katarina [22]3 years ago

8 0

Answer:

2x+3(10+x)

Step-by-step explanation:

I'm not sure but I think this might be the answer

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Point B lies between points A and C on AC. Let x

pashok25 [27]

Answer:

see below

Step-by-step explanation:

Since AB + BC = AC, x + 3x = 20 → 4x = 20 → x = 5.

AB = x = 5 and BC = 3x = 3 * 5 = 15.

3 0

3 years ago

How do i do this????

yarga [219]

Blank 1=8

Blank 2=3

Blank 3=11

8 0

3 years ago

Read 2 more answers

The wettest April for Albuquerque, NM, was recorded in 1905. The amount was 1.2in more than the amount recorded for the second w

SCORPION-xisa [38]

The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2

4 0

4 years ago

What is the solution: 256x + 2 = 43x + 9

ruslelena [56]

Answer:

$x = \bf \frac{7}{213}$

Step-by-step explanation:

To find the solution to the equation, we have to rearrange the equation to make $x$ the subject:

$256x + 2 = 43x + 9$

⇒ $256x + 2 - 2 = 43x + 9 - 2$ [Subtracting 2 from both sides]

⇒ $256x = 43x + 7$

⇒ $256x - 43x = 43x + 7 - 43x$ [Subtracting $43x$ from each side]

⇒ $213x = 7$

⇒ $\frac{213}{213}x = \frac{7}{213}$ [Diving both sides by 213]

⇒ $x = \bf \frac{7}{213}$

3 0

1 year ago

Read 2 more answers

A tank contains 90 kg of salt and 1000 L of water. A solution of a concentration 0.045 kg of salt per liter enters a tank at the

Andreyy89

Answer:

Step-by-step explanation:

concentration = amount of salt/solution

A) Initial concentration= 90/1000 = 0.09

Q = quantity of salt

Q(0) = 90 kg

Inflow rate = 8 l/min

Outflow rate = 8 l/min

Solution = 1000 L at any time t.

Salt inflow = 0.045 * 8 per minute

= 0.36 kg per minute

This is mixed and drains from the tank.

Outflow = $\frac{Q(t)}{1000}$

Thus rate of change of salt

Q'(t) = inflow - outflow = $0.36-\frac{Q(t)}{1000} \\=\frac{360-Q(t)}{1000}$

Separate the variables and integrate

$\frac{1000dQ}{360-q(t)} =dt\\-1000 ln |360-Q(t)| = t+C\\ln |360-Q(t)| = -0.001+C'\\360-Q(t) = Ae^{-0.001t} \\Q(t) = 360-Ae^{-0.001t}$

Use the fact that Q(0) = 90

90 = 360-A

A = 270

$Q(t) = 360-270e^{-0.001t}$

B) Q(t) = 360-270e^-0.004 = 91.07784

C) When t approaches infinity, we get

Q(t) tends to 360

So concentration =360/1000 = 0.36

8 0

3 years ago