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NikAS [45]
2 years ago
11

A ruler costs pence.

Mathematics
1 answer:
Katarina [22]2 years ago
8 0

Answer:

2x+3(10+x)

Step-by-step explanation:

I'm not sure but I think this might be the answer

You might be interested in
Based on the model ​N(11541154​,8686​) describing steer​ weights, what are the cutoff values for ​a) the highest​ 10% of the​ we
yaroslaw [1]

Answer:

a) x = 1225.68

b) x = 1081.76

c)  1109.28 < x < 1198.72

Step-by-step explanation:

Given:

- Th random variable X for steer weight follows a normal distribution:

                                    X~ N( 1154 , 86 )

Find:

a) the highest​ 10% of the​ weights? ​

b) the lowest​ 20% of the​ weights? ​

c) the middle​ 40% of the​ weights? ​

Solution:

a)

We will compute the corresponding Z-value for highest cut off 10%:

                                   Z @ 0.10 = 1.28

                                    Z = (x-u) / sd

Where,

u: Mean of the distribution.

s.d: Standard deviation of the distribution.

                                   1.28 = (x - 1154) / 86

                                      x = 1.28*86 + 1154

                                      x = 1225.68

b)

We will compute the corresponding Z-value for lowest cut off 20%:

                                   -Z @ 0.20 = -0.84

                                    Z = (x-u) / sd

                                   -0.84 = (x - 1154) / 86

                                      x = -0.84*86 + 1154

                                      x = 1081.76

c)

We will compute the corresponding Z-value for middle cut off 40%:

                                    Z @ 0.3 = -0.52

                                    Z @ 0.7 = 0.52

                                    [email protected] < x < [email protected]

                       -.52*86 + 1154 < x < 0.52*86 + 1154

                                  1109.28 < x < 1198.72

7 0
3 years ago
The Math 123 book includes about 230 pages (not including the back parts of the book). If you aim to complete 65% of all the pag
alina1380 [7]

Answer: 150 pages

Step-by-step explanation:

I usually just multiply the number by the percentage and it works out just fine :)

8 0
3 years ago
Y=2/3x-1 ×=-6,-3,0,3​
Y_Kistochka [10]

Answer:

y=-5,-3,-1,1 are value for y

4 0
2 years ago
Students who have completed a speed reading course have reading speeds that are normally distributed with a mean of 950 words pe
VikaD [51]

Answer:

36.04% probability that at most two of them would read at less than 850 words per minute

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of students who read less than 850 words per minute.

Pvalue of Z when X = 850. The mean is \mu = 950 and the standard deviation is \sigma = 200

Z = \frac{X - \mu}{\sigma}

Z = \frac{850 - 950}{200}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85 of students read less than 850 words per minute.

If 10 students are selected at random, what is the probability that at most two of them would read at less than 850 words per minute

This is P(X \leq 2) when n = 10, p = 0.3085. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3085)^{0}.(0.6915)^{10} = 0.0250

P(X = 1) = C_{10,1}.(0.3085)^{1}.(0.6915)^{9} = 0.1115

P(X = 2) = C_{10,2}.(0.3085)^{2}.(0.6915)^{8} = 0.2239

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0250 + 0.1115 + 0.2239 = 0.3604

36.04% probability that at most two of them would read at less than 850 words per minute

8 0
3 years ago
Please help with a.<br><br> Explain how you got your answer. Don’t use a calculator.
kumpel [21]

Answer:

The first one simplified is 3

And the second one is 3 as well

Step-by-step explanation:

Hope this helps

6 0
3 years ago
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