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Nimfa-mama [501]
3 years ago
13

Can someone help me with prombelm number 2

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
Question 2
H(x)=x^2-5x+7

h(2)=2^2-5(2)+7
4-10+7
-6+7
1

h(-5)=-5^2-5(-5)+7
10+25+7
35+7
42

h(-8)=-8^2-5(-8)+7
16+30+7
46+7
53


a. 1
b.42
c.53
Andrews [41]3 years ago
6 0

Answer:

Work shown below!

Step-by-step explanation:

2. g(x)=\frac{1}{2}x+5

g(4) =\frac{1}{2}*\frac{4}{1} +5= 2+5=7

g(-10)=\frac{1}{2}*\frac{-10}{1}+5=-5+5=0

g(0)=\frac{1}{2} *\frac{0}{1} +5=0+5=5

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Lostsunrise [7]

Answer:

The choice second

y =  \frac{1}{3}  \times ( \frac{1}{4} ) ^{x}

3 0
2 years ago
Rewrite each equation in slope-intercept form, if necessary. Then determine whether the lines are parallel. Explain,
Oksana_A [137]
Answer:
d

Step-by-step explanation:

Slope intercept form: y = mx + b

y = -x + 7
x + y = 21

x + y = 21
-x -x
y = -x + 21


y = -x + 7
y = -x + 21

Parallel lines have the same slope. Here, our slope is -1

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Hope this helps!
8 0
2 years ago
Estimate each product 1/5 x 24
antoniya [11.8K]

Answer:

4.8

Step-by-step explanation:

Um, I'm not sure how to explain, but watch a khan academy video on it

3 0
3 years ago
17) List the ways five dogs a Beagle, a Collie, a Greyhound, a Poodle and a
Gnoma [55]

Answer:

  • <u>10 pairs</u>
  • <u>It is a combination</u>

<u></u>

Explanation:

This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.

The formula for combinations is:

           C(m,n)=\dfrac{m!}{n!\cdot (m-n)!}

For five diffferent dogs to be put in pairs, the number of different pairs is:

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4 0
3 years ago
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Fittoniya [83]

Answer:

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2. A=1/2x6(12+4

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6 0
3 years ago
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