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Nimfa-mama [501]
3 years ago
13

Can someone help me with prombelm number 2

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
Question 2
H(x)=x^2-5x+7

h(2)=2^2-5(2)+7
4-10+7
-6+7
1

h(-5)=-5^2-5(-5)+7
10+25+7
35+7
42

h(-8)=-8^2-5(-8)+7
16+30+7
46+7
53


a. 1
b.42
c.53
Andrews [41]3 years ago
6 0

Answer:

Work shown below!

Step-by-step explanation:

2. g(x)=\frac{1}{2}x+5

g(4) =\frac{1}{2}*\frac{4}{1} +5= 2+5=7

g(-10)=\frac{1}{2}*\frac{-10}{1}+5=-5+5=0

g(0)=\frac{1}{2} *\frac{0}{1} +5=0+5=5

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guajiro [1.7K]

Answer:

D

Step-by-step explanation:

If I estmaite the answer from 81% to 80%, then 80*2=160. 160/2=80. 80% to 81 percent.

--------------------------------------------------------------------------------

Hope this helps you...

6 0
3 years ago
What is the value of x? The figure is not drawn to scale. Show work
Alecsey [184]

Answer:

x = 21.

Step-by-step explanation:

AS there are parallel lines:

4/12 = 7/x

4x = 84

x = 84/4 = 21.

8 0
2 years ago
Help me please!!
Mice21 [21]

Answer:

1.) - 1/2

2.) the slope is 0 which means it is a vertical line

Step-by-step explanation:

In order to solve this you take the formula

y-y / x-x

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7 0
3 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
What is 453-259 with your work bring shown
photoshop1234 [79]
The answer is 194 you have to carry on

5 0
3 years ago
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