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GrogVix [38]
2 years ago
6

What is the minimum y value of the following quadratic function? f(x) = x2 - 6x + 8

Mathematics
1 answer:
tia_tia [17]2 years ago
8 0

Answer:

14

Step-by-step explanation:

k

=

c

−

b

2

4

a

We know that

a

=

1

,

b

=

−

8

and

c

=

2

, so let's substitute:

k

=

2

−

(

−

8

)

2

4

(

1

)

=

2

−

64

4

=

2

−

16

=

−

14

.

So, we have

min

=

−

14

. Let's check:

graph{(x^2 - 8x + 2 - y)(-14 -y)=0 [-11.82, 20.22, -15.38, 0.64]}

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