Ask question

Ask question

All categories

3 years ago

15

DEFINE ALL OF THESE, ONE SENTENCE EACH, PLEASE

1 answer:

coldgirl [10]3 years ago

7 0

<u>Answers:</u>

These are the three major and pure mathematical problems that are unsolved when it comes to large numbers.

The Kissing Number Problem: It is a sphere packing problem that includes spheres. Group spheres are packed in space or region has kissing numbers. The kissing numbers are the number of spheres touched by a sphere.

The Unknotting Problem: It the algorithmic recognition of the unknot that can be achieved from a knot. It defined the algorithm that can be used between the unknot and knot representation of a closely looped rope.

The Large Cardinal Project: it says that infinite sets come in different sizes and they are represented with Hebrew letter aleph. Also, these sets are named based on their sizes. Naming starts from small-0 and further, prefixed aleph before them. eg: aleph-zero.

You might be interested in

Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.

Fed [463]

Answer:

The area of the sector BOC is A' = 31.4 $cm^{2}$

Step-by-step explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector $\theta$ = 36°

Area of the circle A = $\pi r^{2}$

A = 3.14 × $0.1^{2}$ = 0.0314 $m^{2}$

Now area of the sector BOC is

$A' = A (\frac{\theta}{360} )$

$A' = 0.0314 (\frac{36}{360} )$

A' = 0.00314 $m^{2}$ = 31.4 $cm^{2}$

Therefore the area of the sector BOC is A' = 31.4 $cm^{2}$

7 0

4 years ago

Evaluate 1/4 c + 3d when c = 6 and d = 7

Naddika [18.5K]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Replace c with 6, and d with 7:-

$\Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}$

$\bigstar$ On simplification,

$\Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4} +21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}$

$\bigstar$ Adding the numerators,

$\Large\text{$\displaystyle\frac{90}{4}$}$

$\bigstar$ Finally, Reducing the fraction:-

$\Large\text{$\displaystyle\frac{45}{2}$}$

$\Uparrow$ $\mathbb{OUR\:SIMPLIFIED\:EXPRESSION}$

<h3>Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

8 0

2 years ago

Read 2 more answers

samuel needs to mail a package to his friend in new york. he places an address label with length represented by the function f(x

dimaraw [331]

Answer:

what is the question

Step-by-step explanation:

3 0

4 years ago

How can you solve 30×20 using compatible numbers

Olin [163]

You could go 3×10 × 10×2

5 0

4 years ago

What is a budget? Describe the four-step process of figuring out your monthly budget.

Len [333]

I believe the answer is C. It is the only one that makes sense

3 0

3 years ago