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2 years ago

DEFINE ALL OF THESE, ONE SENTENCE EACH, PLEASE

Mathematics

1 answer:

coldgirl [10]2 years ago

7 0

<u>Answers:</u>

These are the three major and pure mathematical problems that are unsolved when it comes to large numbers.

The Kissing Number Problem: It is a sphere packing problem that includes spheres. Group spheres are packed in space or region has kissing numbers. The kissing numbers are the number of spheres touched by a sphere.

The Unknotting Problem: It the algorithmic recognition of the unknot that can be achieved from a knot. It defined the algorithm that can be used between the unknot and knot representation of a closely looped rope.

The Large Cardinal Project: it says that infinite sets come in different sizes and they are represented with Hebrew letter aleph. Also, these sets are named based on their sizes. Naming starts from small-0 and further, prefixed aleph before them. eg: aleph-zero.

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Giving triangle and m what is m >b

Gelneren [198K]

Since you know the triangles are congruent/equal, you know that:

m∠A and m∠X are congruent and have the same angle, and so does:

m∠B and m∠Y

m∠C and m∠Z

A triangle is 180°. (the 3 angles have to add up to 180) To find m∠B, you can do this:

m∠A + m∠B + m∠C = 180°

21° + m∠B + 35° = 180° Subtract 21 and 35 on both sides

m∠B = 124° your answer is C

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3 years ago

5/8 and 1/4 is subtracted from the product of 2 3/4 and 1 3/5 what is the difference

olga55 [171]

Answer:

-233/40

Step-by-step explanation:

5/8 + 1/4 - 2(3/4 + 13/5)

5/8 + 2/8 - 6/4 + 26/5

7/8 - 30/20 + 104/20

7/8 - 134/20

35/40 - 268/40

-233/40

3 0

3 years ago

What is the length of a diagonal of a cube with a side length of 10 cm? 200 cm 210cm 300 cm 320cm

Scilla [17]

Answer:

The length of the diagonal of the cube = √(3 × 10²) = √300 cm

Step-by-step explanation:

* Lets revise the properties of the cube

- It has six equal faces all of them are squares

- It has 12 vertices

- The diagonal of the cube is the line joining two vertices in opposite

faces (look to the attached figure)

- To find the length of the diagonal do that:

# Find the diagonal of the base using Pythagoras theorem

∵ The length of the side of the cube is L

∵ The base is a square

∴ The length of the diagonal d = √(L² + L²) = √(2L²)

- Now use the diagonal of the base and a side of a side face to find the

diagonal of the cube by Pythagoras theorem

∵ d = √(2L²)

∵ The length of the side of the square = L

∴ The length of the diagonal of the cube = √[d² + L²]

∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root

∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)

* Now lets solve the problem

∵ The length of the side of the square = 10 cm

∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm

- Note: you can find the length of the diagonal of any cube using

this rule Diagonal = √(3L²)

7 0

3 years ago

Read 2 more answers

A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr

Tema [17]

Answer:

a. p1(x) = 2 - x

b. p2(x) = x² - 3*x + 3

c. p1(0.97) = 1.03; p2(0.97) = 1.0309

Step-by-step explanation:

f(x) = 1/x

f'(x) = -1/x²

f''(x) = 2/x³

a = 1

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

7 0

3 years ago

Find the slope of y=1/6x+3/2

Gemiola [76]

The slope is 1/6. y= mx + b
m is always to slope.

6 0

3 years ago

Read 2 more answers